Hi everyone again

This one is linked to my previous 2 question.

Essentially I am trying to use a procedure to reproduce the formula:

S(j) = (1 + sum(H_j*T_j,j=1..n))/(1 + sum(1/(H_j*T_j),j=1..n))

BigProc:= proc(H::list,T::list)
local Form, i;
Form:=[];
for i from 1 to nops(H) do
Form := [op(Form),(1 + [sum(H[1..i]*~T[1..i],i=1..5)])/~(1 + [sum(1/~(H[1..i]*~T[1..i]),i=1..5)])]
end do:
end proc:
MainProc([1,3,5],[3,6,8])

Error, (in sum) summation variable previously assigned, second argument evaluates to 1 = 1 .. 5
 

The actual answer should be (3, 396/25,22320/509)

ie 

S(1) = (1+ 3)/(1+(1/3)) = 3

S(2) = (1 +(3+18))/(1+1/3 + 1/18)) = 396/25

S(3) = (1 +(3+18+40))/(1+1/3 + 1/18 +1/40) = 22320/509

I feel like I am missing a few things to my procedure. Any help would be greatly appreciated!

The output of a solve command was:

solution := {p[1] = 2.788944999, p[2] = 4.940143518}, { p[1] = 15.29764736, p[2] = 4.946617373}

My question is: How to capture these 4 numbers in a 2 by 2 matrix ?

I tried assign, subs commands. Did not succeed. Could some one help, please?

Hi

I would like to be able to use a procedure in order to create a sequence using a list. Here is an example of what I am trying to achieve:

X = [1,3,4, 50,10]

T_n = 1 + sum^n_j=1 X_j

So T_1 = 1 + 1 = 2

T_2 = 1 + [1+3] = 5

T_3 = 1 +[1+3 +4] = 9

T_4 = 1 + [1+3+4+50] = 59

T_5 = 1+ [1+3+4+50+10] = 69

So my final list would be [2,5,9,59,69]

I am quite new to this forum so i was not sure how to create the Sum from j = 1 to n bit. I know the command for creating a summation but not in a procedure sense.

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I have managed to get the answers for a), b) and c) manually.

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If you have any idea please advise! thanks