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Najibeh Borhani

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@Kitonum Thanks. I'll try ...

Najibeh Borhani 50
June 09 2022
0 0

@Kitonum Thanks. I'll try 

@tomleslie thanks for your time, he...

Najibeh Borhani 50
May 18 2022
0 0

@tomleslie thanks for your time, here the given g(t) is in the form:

> 

ODE := cos(g(t))^2*(diff(T(t), t, t))-3*rho*(diff(g(t), t))*cos(g(t))*sin(g(t))*(diff(T(t), t))+(Omega^2*cos(g(t))^z-8*rho^2*(diff(g(t), t))^2*sin(g(t))^2+2*sin(g(t))*cos(g(t))*(diff(g(t), t, t))*rho+2*(cos(g(t))^2)(diff(g(t), t))^2*rho+2*rho*(diff(g(t), t))^2*sin(g(t))^2)*T(t) = 0

cos(g(t))^2*(diff(diff(T(t), t), t))-3*rho*(diff(g(t), t))*cos(g(t))*sin(g(t))*(diff(T(t), t))+(Omega^2*cos(g(t))^z-8*rho^2*(diff(g(t), t))^2*sin(g(t))^2+2*sin(g(t))*cos(g(t))*(diff(diff(g(t), t), t))*rho+2*(cos(g(t)))(diff(g(t), t))^4*rho+2*rho*(diff(g(t), t))^2*sin(g(t))^2)*T(t) = 0

 (1)
> 

"g(t):=sqrt(lambda)*((1)/(2)-(sqrt(2)*(beta+gamma+8 Pi)*t)/(sqrt(3)*(gamma+8 Pi)))"

proc (t) options operator, arrow, function_assign; sqrt(lambda)*(1/2-sqrt(2)*(beta+gamma+8*Pi)*t/(sqrt(3)*(gamma+8*Pi))) end proc

 (2)
> 

ODE

cos(lambda^(1/2)*(1/2-(1/3)*2^(1/2)*(beta+gamma+8*Pi)*t*3^(1/2)/(gamma+8*Pi)))^2*(diff(diff(T(t), t), t))+rho*lambda^(1/2)*2^(1/2)*(beta+gamma+8*Pi)*3^(1/2)*cos(lambda^(1/2)*(1/2-(1/3)*2^(1/2)*(beta+gamma+8*Pi)*t*3^(1/2)/(gamma+8*Pi)))*sin(lambda^(1/2)*(1/2-(1/3)*2^(1/2)*(beta+gamma+8*Pi)*t*3^(1/2)/(gamma+8*Pi)))*(diff(T(t), t))/(gamma+8*Pi)+(Omega^2*cos(lambda^(1/2)*(1/2-(1/3)*2^(1/2)*(beta+gamma+8*Pi)*t*3^(1/2)/(gamma+8*Pi)))^z-(16/3)*rho^2*lambda*(beta+gamma+8*Pi)^2*sin(lambda^(1/2)*(1/2-(1/3)*2^(1/2)*(beta+gamma+8*Pi)*t*3^(1/2)/(gamma+8*Pi)))^2/(gamma+8*Pi)^2+2*(cos(lambda^(1/2)*(1/2-(1/3)*2^(1/2)*(beta+gamma+8*Pi)*t*3^(1/2)/(gamma+8*Pi))))(-(1/3)*lambda^(1/2)*2^(1/2)*(beta+gamma+8*Pi)*3^(1/2)/(gamma+8*Pi))^4*rho+(4/3)*rho*lambda*(beta+gamma+8*Pi)^2*sin(lambda^(1/2)*(1/2-(1/3)*2^(1/2)*(beta+gamma+8*Pi)*t*3^(1/2)/(gamma+8*Pi)))^2/(gamma+8*Pi)^2)*T(t) = 0

 (3)
> 

``


 

Download ode_rlmt.mw

 

@dharr I really appreciate your hel...

Najibeh Borhani 50
March 03 2022
0 0

@dharr I really appreciate your help. 🙏🏻🙏🏻🙏🏻

@Thomas Richard Actually it's n...

Najibeh Borhani 50
February 24 2022
0 0

@Thomas Richard Actually it's not my work I'm trying to do something similar. And about integer, in my case the order is non-integer, right? So what the output is like the case 2

 

 

@mmcdara I really appreciate your h...

Najibeh Borhani 50
February 24 2022
0 0

@mmcdara I really appreciate your help. Thank you🙏🏻🙏🏻🙏🏻

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