@tomleslie 

sir it seem little bit ok but I am afraid from the title of each plot that in ist plot you used the value of k=0.1,0.3,0.5,0.7,0.9 but the value of Q=0.1645 and lambda=0.0096 means that just changes the value of k but Q and lamda remain fixed??

similarly in second plot for k=0.1,0.3,0.5,0.7,0.9 and the value of Q=0.4392 and lambda=0.0093. while in both case, fixed the value of We=0.1, Br=0.3 and x=0.

The Idea that I want to apply here  is 

for k=0.1, the corresponding value of Q=0.5617 and lambda=0.0096, k=0.3 the corresponding value of Q=0.4392 and lambda=0.0010, for k=0.5 the corresponding value of Q=0.2564 and lambd=0.0093, for k=0.7 the corresponding value Q=0.1645 and lambda=0.0075, and for k=0.9, the corresponding value of Q=0.0659 and lambda=0.0031.

So, these 5 curve want to plot in one plot. Beside the value of We=0.1, Br=0.3 and x=0 remain fixed.

Sir, can you please add little explaination of the code to understand it.

Hopefully, I cleared the idea that i want to plot and thanks alot your help.

@tomleslie thnak you for great help

@tomleslie thank you for help. The code is almost according to desire but is it possible that the upper part of the picture also look as the base portion? and how to control the orientation of the graph?

@tomleslie The code is Ok as per need. Sir let me try more about the issue 

1-Their are 25 plots, organised as 5*5. I need only on plot dnt need of 25 plots. See example below.

2- Each individaul plot contains nine curves but I required 5 curve in each curve beacuse The code have Q=[0.5617, 0.4392, 0.2564, 0.1645, 0.0659] and lambda=[0.0096, 0.0010, 0.0093, 0.0075, 0.0031], you can oberved that their are 5 values of Q and Lambda. So we draw 5 curve in plot means k=0.1,0.3,0.5,0.7,0.9.

please see the digram as a reference

@tomleslie Sir thanks for your comment and help. Can you please explain about Arrplt? please convert this command into noraml display beacuse when i copy to paste into file its looks stratched. Sir, I observed that  ploted value of Q and Lmabda are againt for k=0.1,0.3,0.5,0.7,0.9 and We=0.1,0.3,0.5,0.7,0.9 but in graph you draw for k=0.1,0.2,,,0.9.

Here is mylittle  explaining for problem, 

I want to chect the impact of k, We on theta; at x=0,and n=0, range for y=-1..1, for this the value of k =0.1,0.3,0.5,0.7,0.9 and by fixing the value of We=0.1 and the value of Br=0.3. For the the value of Q=0.5617,0.4392,0.2564,0.1645,0.0659 and λ=0.0096, 0.0010,0.0093,0.0075,0.0031.

now repeat the above step for We on theta; at x=0, Br=0.3 and n=0, range for y=-1..1 ,for this the value of  We=0.1,0.3,0.5,0.7,0.9 and by fixing the value of k=0.1 and the value of Br=0.3. For the the value of Q=0.2317,0.4392,0.6564,0.7645,0.0859 and λ=0.0196, 0.0231,0.2356,0.3575,0.5631.

@tomleslie Thanks sir

@Mariusz Iwaniuk I am also using Mpaple 22. Can you please uplaod mapleworksheet after runing on your system?

@dharr  I am confuse how to apply loop for my problem for these type of values. kindly help me to run code and get the results.

@dharr sir i explaind in detail the value of Q and lambda at the end of code in maple worksheet . For example

 I want to chect the impact of k, We and Br on θ at x=0 and n=0,  for this the value of k =0.1,0.3,0.5,0.7,0.9 and by fixing the value of We=0.1 and the value of Br=0.3. For the the value of Q=0.5617,0.4392,0.2564,0.1645,0.0659 and λ=0.0096, 0.0010,0.0093,0.0075,0.0031.`

@dharr I have fixed but still do not get the output. please check

ODE_Numeric_solution_help.mw

@dharr it's written mistakenly. Actually, I want to solve for theta as a function of y.

@tomleslie Sir, I have fixederror and now the file is working accordingly. 

@Thomas Richard 

Sir, I am trying to explian the concept which i want to apply on the problem. Beside this Isimplified the ODE in attached picture. We can suppose the value of n=2. 

1-The boundary condition for zeroth, ist and 2nd order ode alos defened.

Help.pdf

@tomleslie Thank sir for your comment. You always help me, whenever i posted at this forum.

Sir, I am trying to explian the concept which i want to apply on the problem. Beside this Isimplified the ODE in attached picture. We can suppose the value of n=2. 

1-The boundary condition for zeroth, ist and 2nd order ode alos defened.

Help.pdf

Please PDF file to extract idea that want to apply.

Help.pdf