Bart

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8 years, 121 days

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These are questions asked by Bart

Hi,

There seems to be an issue with pdsolve, which is similar to https://mapleprimes.com/questions/222498-Issues-With-Pdsolve.

pdsolve([diff(u(x, t), t) = diff(u(x, t), x, x), u(x, 0) = 1, u(0, t) = 0, u(2, t) = 0]); # works

pdsolve([diff(u(t, x), t) = diff(u(t, x), x, x), u(0, x) = 1, u(t, 0) = 0, u(t, 2) = 0]); # swapped arguments, works

pdsolve([diff(u(x, t), t) = diff(u(x, t), x, x), u(x, 0) = 1, u(-1, t) = 0, u(1, t) = 0]); # translate by -1, works

pdsolve([diff(u(t, x), t) = diff(u(t, x), x, x), u(0, x) = 1, u(t, -1) = 0, u(t, 1) = 0]); # swapped arguments and translate by -1, doesn't work

The solution for the last example doesn't incorporate the initial condition correctly, while it is the same as the third example (except for swapped arguments). Not sure if this is still a problem in Maple 2019, though.

Hi,

I'm using the eBookTools package to convert a .mw file as a chapter into a PDF file. However, a problem arises when I convert a document with a few repeated plotting commands (such as plot(x^2)). The issue is that in the final PDF the images of the various plots overlap, and that the individual plots can't be clearly seen. Is there a resolution to this?

Thanks,
Bart

will give me

which is indeed a solution of the PDE1

will give me

which is not a solution of the PDE2

However, both differential equations are equal, only the arguments are swapped around. Am I doing something wrong, or is this a bug?

Thanks

Hi,

When I execute the command

series(exp(x),x)

and then refer to the equation in a new execution group using a equation label (CTRL-L on Windows), the equation is shown in Maple 18, but in Maple 2015 I get an error message: 'Error, missing operator or ';'. Using the % instead does work for both versions.

Is this intended behaviour or a bug in Maple 2015?

Thanks,

Bart

Hi,

 

I encountered the following problem in Maple 14

expr1:=sqrt(a)

assume(a>0)

expr2:=sqrt(a)

additionally(a>1)

subs(a=2,expr1) #gives correct answer of sqrt(2)

subs(a=2,expr2) #does not substitute a=2 in expr2

It seems the last statement with expr2 does not work as expected, I wondered why this behaviour is so, because it does work with expr1. The added assumption does not invalidate the first...

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