s:= int((1/4)*sqrt(2)*exp(-(1/2)*(x+k*sin(-theta+phi))^2/sigma^2)*(1/(2*Pi)+Q*cos(k*phi))/(Pi^(3/2)*sigma), phi = -Pi .. Pi);

I really need a result to the integration below but Maple 13 just won't return one. Could you please help me or advise me as to what might be wrong or what I might try ? I'm integrating on the real line in x but even when I alter the limits of integration maple just returns the integrand.

s1:= int((1/8)*sqrt(2)*exp((1/2)*k^2*cos(x)^2/sigma^2)*exp(-(1/2)*k^2/sigma^2...

The integrals are

v1:=int((1/(2*Pi) + Q* cos(k*phi))^2/ (1+ beta^2*((1/(2*Pi)) + Q* cos(k*phi) )^2),phi=-Pi..Pi);

v2:=int((1/(2*Pi) + Q* cos(k*phi))^2*cos(k*phi)/ (1+ beta^2*((1/(2*Pi)) + Q* cos(k*phi) )^2),phi=-Pi..Pi);

v3:=int((1/(2*Pi) + Q* cos(k*phi))^3*cos(k*phi)/ ((1+ beta^2*((1/(2*Pi)) + Q* cos(k*phi) )^2))^2,phi=-Pi..Pi);

v4 := int(exp((-1/2)*((psi-theta-k*sin(theta-phi))/sigma)^2),phi = - Pi ..Pi);

Hi,

I am trying to simplify the expression s as given below. (I am not sure why it comes up with all the vector caclulus notation in it but it should display okay when you enter it)

Because of the presence of the exponential imaginary fucntions I thought evalc might be useful but when I use it I get a huge expression with csgn appearing in it. To my knowledge csgn appears when assumptions are not correctly specified - is this so? I can't see any assumption...

What I mean is for example, the series

# 1-t+t^2-t^3+...;         -----------------------(1)

equals to

1/(1+t); # modulus of t < 1 --------------(2)

so given the terms in (1) above could maple deduce (2)  ?