Ronan

@nutnutman Firstly "vv 575" substitution method is really excellent. I decided to try a bit more complex too. Higher order derivatives and mixed derivatives. I looked at the link you provided, I didn't have a clue either. Have not used the substitution method here but it could be applied.

The Next 2 lines are just testing

sum(a^i, i = 1 .. 6)+sum(a^i, i = 8 .. 3)+sum(a^i, i = 5 .. 10)+a^7+a^4

(1)

sum(a^i, i = 1 .. l-1)+sum(a^i, i = l+1 .. p-1)+sum(a^i, i = p+1 .. 10)+a^l+a^p

(2)

s := sum((sum(f[t](x[i, k], a[k]), k = 1 .. l-1)+sum(f[t](x[i, k], a[k]), k = l+1 .. p-1)+sum(f[t](x[i, k], a[k]), k = p+1 .. n)+f[t](x[i, l], a[l])+f[t](x[i, p], a[p]))^2, i = 1 .. m)

sum((sum(f[t](x[i, k], a[k]), k = 1 .. l-1)+sum(f[t](x[i, k], a[k]), k = l+1 .. p-1)+sum(f[t](x[i, k], a[k]), k = p+1 .. n)+f[t](x[i, l], a[l])+f[t](x[i, p], a[p]))^2, i = 1 .. m)

(3)

dsa[l] := diff(s, a[l])

sum(2*(sum(f[t](x[i, k], a[k]), k = 1 .. l-1)+sum(f[t](x[i, k], a[k]), k = l+1 .. p-1)+sum(f[t](x[i, k], a[k]), k = p+1 .. n)+f[t](x[i, l], a[l])+f[t](x[i, p], a[p]))*(diff(f[t](x[i, l], a[l]), a[l])), i = 1 .. m)

(4)

d2sa[l] := diff(s, a[l], a[l])

sum(2*(diff(f[t](x[i, l], a[l]), a[l]))^2+2*(sum(f[t](x[i, k], a[k]), k = 1 .. l-1)+sum(f[t](x[i, k], a[k]), k = l+1 .. p-1)+sum(f[t](x[i, k], a[k]), k = p+1 .. n)+f[t](x[i, l], a[l])+f[t](x[i, p], a[p]))*(diff(diff(f[t](x[i, l], a[l]), a[l]), a[l])), i = 1 .. m)

(5)

dsa[p] := diff(s, a[p])

sum(2*(sum(f[t](x[i, k], a[k]), k = 1 .. l-1)+sum(f[t](x[i, k], a[k]), k = l+1 .. p-1)+sum(f[t](x[i, k], a[k]), k = p+1 .. n)+f[t](x[i, l], a[l])+f[t](x[i, p], a[p]))*(diff(f[t](x[i, p], a[p]), a[p])), i = 1 .. m)

(6)

d3 := diff(s, a[l], a[p])

sum(2*(diff(f[t](x[i, p], a[p]), a[p]))*(diff(f[t](x[i, l], a[l]), a[l])), i = 1 .. m)

(7)

d4 := diff(s, a[l], a[p], a[p])

sum(2*(diff(diff(f[t](x[i, p], a[p]), a[p]), a[p]))*(diff(f[t](x[i, l], a[l]), a[l])), i = 1 .. m)

(8)

Download diff_sum_2.mw

Nice One...

Answered: Ronan 847

February 02 2016

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@vv Never thought of "subs" and being able to add them that way.

Thank you...

Answered: Ronan 847

February 01 2016

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@Carl Love That is a point I wasn't sure about myself.

You have to put some work in....

Answered: Ronan 847

February 01 2016

0 0

@nutnutman

What I posted was just an idea. Don't really know what you are doing. Post a work sheet (as I did) with a more complex example. That might encourage others to look at the problem. Nobody wants to retype complex formulas.

Solidworks Version...

Answered: Ronan 847

January 01 2016

0 0

I am using Maple 18. Documentation says Solidworks 2013 required. I am on SW 2015. Connection won't open. Have you access to SW 2013?

Thanks...

Answered: Ronan 847

December 25 2014

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@Kitonum That works quitew well.

That Worked...

Answered: Ronan 847

May 28 2014

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@Thomas Richard Thank You

Indeed: How to prove?...

Answered: Ronan 847

June 26 2013

0 0

Well I can't see a way. I was oringinaly asking hopeing maple could automatically reduce the answer. The original problem was to do with a problem in Rational Trigonometry. I wandered off into the weeds working it out (with the help of Maple) as my answer shows. Here is a link to how the solution is arrived at http://www.youtube.com/watch?v=FsQb0_Lgphc&list=PL3C58498718451C47 . I guess one would need to evaluate/ relate both solutions and see how one relates to the other. I don't have a tidy worksheet that is worth posting. I could do one though.

Indeed: How to prove?...

Commented: Ronan 847

June 26 2013

Well I can't see a way. I was oringinaly asking hopeing maple could automatically reduce the answer. The original problem was to do with a problem in Rational Trigonometry. I wandered off into the weeds working it out (with the help of Maple) as my answer shows. Here is a link to how the solution is arrived at http://www.youtube.com/watch?v=FsQb0_Lgphc&list=PL3C58498718451C47 . I guess one would need to evaluate/ relate both solutions and see how one relates to the other. I don't have a tidy worksheet that is worth posting. I could do one though.