dharr

Dr. David Harrington

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20 years, 335 days
University of Victoria
Professor or university staff
Victoria, British Columbia, Canada

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I am a retired professor of chemistry at the University of Victoria, BC, Canada. My research areas are electrochemistry and surface science. I have been a user of Maple since about 1990.

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These are answers submitted by dharr

If you just want a nice equation in powerpoint, as opposed to getting the formula into mathtype, then you can export the maple worksheet as *.rtf, open it in Word, and then copy the equation from Word to Powerpoint

(at least in Windows with Maple 10, this works). Exporting as html and then copying the gif files give much poorer output quality.

Cheers,

David.

See the resultant command. According to the documentation, this uses the subresultant algorithm for low degree polynomials. So you could steal the code in `resultant/subresultant/univar`. I'm not familiar with this algorithm, but perhaps printing out v gives you the sequence you want?

subres:=proc(p,q,x) option`Copyright (c) 1992 by the University of Waterloo. All rights reserved.`;
 local c,d,u,v,r,g,h,du,dv;
 userinfo(2,resultant,`using the subresultant algorithm`);
 u:=p;
 du:=degree(u,x);
 v:=q;
 dv:=degree(v,x);
 c:=1;
 g:=1;
 h:=1;
 userinfo(3,resultant,`degree of inputs is`,du,dv);
 while 0<dv do
   d:=du - dv;
   c:=c*(-1)^(du*dv);
   r:=prem(u,v,x);
   u:=v;
   v:=r;
   print(v);
   du:=dv;
   dv:=degree(r,x);
   userinfo(3,resultant,`degree of pseudo remainder = `||dv);
   divide(v,g*h^d,'v');
   g:=coeff(u,x,du);
   if d=1 then
     h:=g
   else
     h:=iquo(g^d,h^(d - 1))
   end if
 end do;
 c*iquo(v^du,h^(du - 1))
end proc:

and then

subres(3*x^4+x^2+5,x^3+3*x-7,x);

gives the output:

5-8*x^2+21*x

-343+673*x

6171072

96423

 

If you don't care whether or not your matrix is symmetric or Hermitian, then you can use any nonsingular matrix, R to transform your diagonal matrix of eigenvalues.

R.D.R^(-1);

So you can generate R using RandomMatrix, but you should check that it is nonsingular. This is still not the most general way, but is useful for most purposes (the matrices generated are diagonalizable, with diagonal Jordon forms).

I don't have v11, so I can't see everything on your worksheet, but the following idea should work. If your global "constant" is r and the functions defining your parametric plot are something like

alpha:=x->r*sin(x);
beta:=x->r*cos(x);

then you can plot curves with several r values by

plots[display](seq(plot([alpha,beta,0..2*Pi]),r=[1,3,5]));

If you want more individual control over the plots, e.g. different colors, then you can store the plots in variables and then use display to put them together .

David.

 

Eval(y,x=0);

gives

Eval(y,x=0);

(though the Maple tag seems not to display it well in the post). This is the mathematical equivalent of your statement in words.

 

interface(displayprecision=3);

should do the trick.

 

 

Try phaseportrait or DEplot in the DEtools package.

There is a missing line in your output - a list of integers which can be converted to known mersenne primes. My output has the following line after the first "end if":

w := [2, 3, 5, 7, 13, 17, 19, 31, 61, 89, 107, 127, 521, 607, 1279, 2203, 2281, 3217, 4253, 4423, 9689, 9941, 11213, 19937, 21701, 23209, 44497, 86243, 110503, 132049, 216091, 756839, 859433, 1257787, 1398269, 2976221, 3021377, 6972593, 13466917, 20996011, 24036583, 25964951, NULL];

So the routine has no smarts... Try showstat if you can't see it on another try.

 

If you think about eval([x,y],{x=0,y=-1}) giving [0,-1], then you can work this up with map2 to give what you want:

q:={x = 0, y = -1}, {x = 3/4, y = -7/16}:

map2(eval,[x,y],[q])[];

gives

[0,1],[3/4,-7/16]

as required. This works for any number of solutions returned by solve.

 

Sorry, bad copying job; it is op(0,q) which gives y. But note that op(q) is the same as op(1,q) in this context.
q:=y[2]; Then op(q); gives 2 and op(1,q) gives y
As Robert Israel points out, in a Maple plot, you need to specify all parameters. If you want to see how the plot changes with parameter k, then you can plot a 3d plot, with k as one of the axes plot3d(k*x^2 - k*x^4,x=-10..10,k=-10..10); If a plot has a universal shape, then it can be non-dimensionalized, and the non-dimensionalized plot then encapsulates all possible behaviors. For your case of x=k, one defines the (nondimensional variable) X=x/k, and then plots X=1. For the case of y=k*x^2 - k*x^4, let Y=y/k, then Y=x^2 - x^4 has no parameters and can be plotted.
Maybe the @ notation is a nice alternative
(f@x)(t);
           f(x(t))

D(f@x)(t);
           (D(f))(x(t))*(D(x))(t)

convert(%,diff);

           (eval(diff(f(t1), t1), t1 = x(t)))*(diff(x(t), t))

X:=(u,T)->u*cos(T);
Y:=(u,T)->u*sin(T);
plot3d([X(u,T),Y(u,T),u],T=0..2*Pi,u=0..1,axes=boxed);
For these sorts of problems, I usually rename the file to *.txt; often the virus checker is more worried about the end user double-clicking on *.exe or other dangerous filetypes than actually looking closely at the content (unless of course there is a known virus in there!).
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