0 years, 45 days

## Bernoulli DGL y' = y^4 * cos(x) + y*tan(...

Maple

Good Morning Guys,

Please, could somebody help me with my problem in Maple?

The expression y' = y^4 * cos(x) + y*tan(x) with start-value y(0) = 0.5 has the solution of 1/root(cos(x)^2 * 8*cos(x)-3 * sin(x),3).

If I try to solve it with this method dgl_2 := diff(y(x), x) = y(x)^4*cos(x) + y(x)*tan(x) I don't get the right solution. Is it possible to solve this expression with a Tutor app? step by step? If yes I would so happy to tell me how I can do that.

Thanks a lot and I wish you all a nice sunday and stay safe.

## Math Question Diff...

Maple

Hello Guys

Please, sould somebody tell me if my result right or I have do something wrong with maple? THX a lot.

Question was: y' = 1+y^2/x*y

Dgl_1 := diff(y(x), x) = (1 + y(x)^2)/(x*y(x)); result -> Dgl_1 := diff(y(x), x) = (1 + y(x)^2)/(x*y(x))

P := dsolve(Dgl_1, y(x)); result -> P := y(x) = sqrt(_C1*x^2 - 1), y(x) = -sqrt(_C1*x^2 - 1)

THX a lot

## Why Maple can't put correct differentiat...

Hello guys,

I try at the moment to solve this terms:

The function is: f(x,y)=2x2-3xy-(y+2)3+5

1. diff(2*x^2 - 3*xy - (y + 2)^3 + 5, x) = 4x output but this is wrong. The correct output is 4x -3y

2.diff(2*x^2 - 3*xy - (y + 2)^3 + 5, y) = -3*(y + 2)^2 that also wrong. The correct output is -3(x+(y+2)2 )

THX a lot

## Newton’s Method, Diff, diff...

Maple

Hello Guys

I got the Mapple 2022 Student version and I try a couple of time to firgure out why that doesn't work at my Student Version. Please, could anybody help me. Thx a lot.

Newton Method:

f(x) = x^2 assigned to function why I doesn't have right click for this function?

g(x) = x - f(x)/f'(x);

g(1.3) doesn't work because faild he want 2 arguments. That I figure out if I assigned like this

g(x) := x->x f(x)/f'(x) but he do not calc that right. It make me really creapy. Maybe tha Student version doesn't have this fearure is it possible?

This is another think.

a := x^2;

D(a);
2 D(x) x ???? why no 2x?

Next example:

f := x -> 5*x^3 + x - 7

D2f := x -> diff(f(x), x)

D2f:=x->d/dx f(x) ??? why not 15x^2+1?

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