mehdi jafari

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These are replies submitted by mehdi jafari

@torabi if it has phi(z) it is pde ! not ode ! but i assume you should define function of Z , as a parametr , then solve your equations and after that ! solve your pramater.

in your equation, phi is function of z ! but in intergal and thus should be solved ! and then you should solve your ode system ! 

@tomleslie tnx for your help, but your answer is some what different from @Axel Vogt's answer ...

@Axel Vogt tnx it helped and answered, 

@tomleslie i think i have uploaded wrong version, and i will edit and also upload here , and all the problems with unassigned symbols,have been corrected.
i want a closed form solution and plot the result, is that equivalent to evaluate integral numerically and plot the resulting points? if the answer is yes, how can we plot numerical integration?

corrected.mw

@Rouben Rostamian  tnx for quick answer,actually, the problem is finding constants, so as you said, the boundary conditions for this problem should be fixed and then , we should find the constants... 
can we fit the answer to spcefic diagram ? for finding the constants..

@Ramakrishnan 
http://www.mapleprimes.com/questions/150659-How-To-Plot-With-The-Results-Of-Desolve-Command

@vv y is positive... why t should be x ? it can not solved assuming x as a constant number ?

@vv when x and y are between numbers about -100 and 100 this circle like diagram is included ! but when the range is changed to -10000 and 10000 this is not ! why it is happening ?!


 

restart:

eq:=1/(x*y^(2/3))*8.620689655172415*10^(-16)*(-3.11*10^23*x^2*y^(7/6)-3.92*10^19*y^(25/6)+2.14545039999999*10^29*(0.0108*exp(-45.07/y)+exp(-19.98/y^(1/3)-0.00935317203476387*y^2)))/(x+0.015*y^(1.2));

0.8620689655e-15*(-0.3110000000e24*x^2*y^(7/6)-0.3920000000e20*y^(25/6)+0.2317086432e28*exp(-45.07/y)+0.2145450400e30*exp(-19.98/y^(1/3)-0.935317203476387e-2*y^2))/(x*y^(2/3)*(x+0.15e-1*y^1.2))

(1)

 

A:=plots:-implicitplot([eq = 0], x=-100..100,y=0..500, color=[red, blue], thickness=2, gridrefine=3):

B:=plots:-inequal(eq>0,x=-100..100,y=0..500,optionsfeasible = [color = "LightGreen"]):

plots:-display(A,B);

 

A:=plots:-implicitplot([eq = 0], x=-10000..10000,y=0..100000, color=[red, blue], thickness=2, gridrefine=3):

B:=plots:-inequal(eq>0,x=-10000..10000,y=0..100000,optionsfeasible = [color = "LightGreen"]):

plots:-display(A,B);

 

 


 

Download solveee.mw

@vv why y is positive? why y>0 ?

@Sergey Moiseev i know this is a package and i have installed it, but where is this package help ?! and descriptions ?

@Sergey Moiseev whats does options means? i can not search  them in maple help...
 checkexit=10 ?

@tomleslie tnx for your quick answer, please change it to an answer , tnx alot.

@Adri van der Meer tnx for your answer , but actually i want the value for all unknown parameters which will maximize the PP;
i.e, what will be the values for, theta[1],theta[2],phi[1],phi[2],p in which the expression pp will be maximized ?

 

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