salim-barzani

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1 years, 18 days

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These are replies submitted by salim-barzani

@janhardo i dont have time this two day but the function is different but the line is same in one lump we have this function 
f(x, y, t) = theta1*theta2 + Bij(1, 2)
in 2 lump function is different
F__4 = theta[1]*theta[2]*theta[3]*theta[4] + B[12]*theta[3]*theta[4] + B[13]*theta[2]*theta[4] + B[14]*theta[2]*theta[3] + B[23]*theta[1]*theta[4] + B[24]*theta[1]*theta[3] + B[34]*theta[1]*theta[2] + B[12]*B[34] + B[13]*B[24] + B[14]*B[23]
but line is same line just index change line in y[1] we have a[1] and b[1] and in y[2] we have a[2] and b[2] also in this two lump function we have to do change variable  
 {l[3] = conjugate(l[1]), l[4] = conjugate(l[2])}), {l[1] = lR + lI*I, l[2] = hR + hI*I}
is not coming out i have to  work on  it

@janhardo  is about add to line for and 2 y finction with a[1]a[2]b[1]b[2] inside of y[1] and y[2]

@janhardo i will work on too 

@janhardo any new things?

@janhardo  re-upload here they delete again 

@janhardo  in figure , eq(12) contain x' which x' contain t,  is not about two lump is about two line next time i will come to two line first lets fix this y how construct the graph is so different from paper 

@janhardo we did some mistake and i am sure that mistak but i didn't have choice and i am going with it untill i figure out still i am stuck but is so better , i will upload here for you and i will asked a question about this situation if they don't delete, i want you work on it but don't answer that question untill new person which mean new idea come and help us 
first mistake of  our solution must contain t which i fixed , the only point is still i didn't figure out is this why our line is define like that (y=-beta*x/((a^2 + b^2)*alpha + 2*a*beta)-sqrt(30)/6 which is y=(-beta/((a^2 + b^2)*alpha + 2*a*beta)*x+sqrt(-3beta*a(a^2+b^2))/beta*b) i know half of this but this part i don't know where is related to(sqrt(-3beta*a(a^2+b^2))/beta*b)

-Y2-line.mw

@janhardo if need solution mentioned i will upload picture here

of old example which you used already

 

@janhardo  How plot two or three line in one graph like i mention in top together

@janhardo  it will  be great if add a plot with two y[1] and y[2] and lump of them are same how add  another plot for same picture?

@janhardo  is not three lump is a three line each one have a diffrent lump as velocity change 

@janhardo  i try to remove some extra from other example i got something new which is first time i saw this line is true but shape is not is that ok?
becuase in each paper which i saw when a line go from one lump to another lump they have same shape , but in here we don't have this pattern

can we check trajectory difference=0 like last time you did for this example 


 

restart; with(plots); a := 1; b := 1; x1 := -100; y1 := -x1; x2 := 0; y2 := -x2; x3 := 100; y3 := -x3; eq := y = -x; U := proc (x, y, a, b) options operator, arrow; (-12*b^4*y^2+12*(a*y+x)^2*b^2-36*a^2)/(b^4*y^2+(a*y+x)^2*b^2+3*a^2)^2 end proc; contour1 := contourplot(U(x-x1, y-y1, a, b), x = -500 .. 500, y = -300 .. 300, contours = 30, color = red, grid = [100, 100], transparency = .1); contour2 := contourplot(U(x-x2, y-y2, a, b), x = -500 .. 500, y = -300 .. 300, contours = 30, color = blue, grid = [100, 100], transparency = .1); contour3 := contourplot(U(x-x3, y-y3, a, b), x = -500 .. 500, y = -300 .. 300, contours = 30, color = green, grid = [100, 100], transparency = .1); trajectory_plot := implicitplot(eq, x = -500 .. 500, y = -300 .. 300, color = black, thickness = 2); display(contour1, contour2, contour3, trajectory_plot, title = "3-Lump Soliton met Bewegings Trajectorie", labels = ["x", "y"], scaling = constrained, size = [1200, 800])

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y = -x

 

proc (x, y, a, b) options operator, arrow; (-12*b^4*y^2+12*(a*y+x)^2*b^2-36*a^2)/(b^4*y^2+(a*y+x)^2*b^2+3*a^2)^2 end proc

 

 

NULL


 

i fixed this 


 

restart; with(plots); a := 1; b := 1; x1 := -40; y1 := -x1; x2 := 0; y2 := -x2; x3 := 40; y3 := -x3; eq := y = -x; U := proc (x, y, a, b) options operator, arrow; (-12*b^4*y^2+12*(a*y+x)^2*b^2-36*a^2)/(b^4*y^2+(a*y+x)^2*b^2+3*a^2)^2 end proc; contour1 := contourplot(U(x-x1, y-y1, a, b), x = -100 .. 100, y = -80 .. 80, contours = 30, color = red, grid = [100, 100], transparency = .1); contour2 := contourplot(U(x-x2, y-y2, a, b), x = -100 .. 100, y = -80 .. 80, contours = 30, color = blue, grid = [100, 100], transparency = .1); contour3 := contourplot(U(x-x3, y-y3, a, b), x = -100 .. 100, y = -80 .. 80, contours = 30, color = green, grid = [100, 100], transparency = .1); trajectory_plot := implicitplot(eq, x = -100 .. 100, y = -80 .. 80, color = black, thickness = 2); display(contour1, contour2, contour3, trajectory_plot, title = "3-Lump Soliton met Bewegings Trajectorie", labels = ["x", "y"], scaling = constrained, size = [1200, 800])

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y = -x

 

proc (x, y, a, b) options operator, arrow; (-12*b^4*y^2+12*(a*y+x)^2*b^2-36*a^2)/(b^4*y^2+(a*y+x)^2*b^2+3*a^2)^2 end proc

 

 

NULL


 

Download john.mw

Download john.mw

@janhardo this which you upload is for last example is not this example you plot function true a &b are true but this y is from old example , our is y=-x when a=b=1 is so clear from our mw file 

@janhardo this time is Run thanks so much, but john you didn't answer me in last comment , which is 
x1 := -40; y1 := -1/3*x1 - sqrt(30)/6;
x2 := 0;   y2 := -1/3*x2 - sqrt(30)/6;
x3 := 40;  y3 := -1/3*x3 - sqrt(30)/6;
they number but why write like that? have any information? can be any number? 


also in paper mention the time variable t? but in here we don't have a t? and this is you done is a new thing by my openion if i am not wrong? 

john can you do for two and three lump? is same but instead of a & b you have a[1]&b[1] &a[2]&b[2] also for three lump if becuase i need to verify the work for this equation and other the picture already exist but i will upload here too, if you do that the work will be done 

 

@janhardo  why last part is not run, you did a great job, but some question is come up for me 

this equation (eq := y = -1/3*x - sqrt(30)/6;) must be -2/3*x why you subtract some thing  and also why you use (x1 := -40; y1 := -1/3*x1 - sqrt(30)/6;) is a constant and when we replace (contourplot(U(x - x1, y - y1, a, b)) we shifted by this constant 

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