@dharr Every time I read your answer to my question, it brightens my day.
 

@janhardo thank you you did a great job thank you so much

@dharr i don't know where is should add print function u in loop, becuase i have to latex the outcome of u i have do it by hand  but if loop do it it will be amazing, also i need just thus parameter which contain in f (L2), is not different if have thus extra parameter but i don't know why my code not answer is not work when i write solve (L2,{a[1]-a[11]), also if have explicit option it will be great
thanks a lot 

trail-pdetest1.mw

@dharr So you say first i have to check in F1, then substitute in H then pde, that is also true, but i asked a new question related this a hour before, i try  some of this variable all of them not make my pde to zero but some of them do, i want seperate them at there , also if possible in ans[] just find that parameter which belong to our auxiliary function in L2

@janhardo  like that don't have problem but i have to change it by hand all of thus F to f

@dharr  i get exactly bilinear form of that is that like i say need the derivative and i found it , but why when i replace my parameter is not  give me pdetest zero, i try to find parameter a[1]-a[11] alone without other parameter , but didn't give me answer like paper did it , you are so good at finding parameter can you check it please 

Download test.mw

@janhardo can you change the letter F to f (capital to small) becuase i have to copy past equation i  needed also for G to g

@janhardo you answer all question you are going to modify your Ai i like that , just last my question he can't answer thank you it work i have to check it then

@dharr let me give you a hint maybe already you know this, but lineaer part of pde is the same of bilinear equation, and 5 month before macdara write a program for me about how open this derivative and it is totally corect for (1+1) dimension when it is (x,t) but for (x,y,t) and (x,y,z,t) i don't know why not working , i want to check that if i open bilinear equation is the same as linear part or just the shape of bilinear form it is , i will explain more if you needed , 

i though equation 25 is linear part of my pde, the bilinear form it is i am sure %100 percent, but when i open bilinear equation it is equal to linear part or not i am not sure, i have to open by hirota derivstive in here i try it but if watch and make it for 3+1 dimension the prcecure we will be sure about that it is bilinear form or not 

also i check the result i don't know something must be mistake otherwise your code are working so good 

Download test-Blinear.mw

Download system-pdetest.mw

@janhardo i have a lot problem not just this, so i need a systematic progress

@janhardo replaced thus parameter in L2 then L2 in H then do pdetest if is zero then it is correct.

@ecterrab maybe  question is not related to dirac but i ask more than 10 time about this question and i didn't get any answer i want apply long wave limit which i am quit sure it is a technique, i asked a lot time to a lot people but i didn't get my answer i hope you have  idea about  this question,

https://www.mapleprimes.com/questions/240218-How-Apply-Substitution-And-Apply-Limit

i know every structure if have any question please let me know!.

@ecterrab  i have some question in a topic maybe you faced before can i ask the question ?

@janhardo  i know every structure of the topic in theory but when i come to apply by maple is making problem in 2 part finding long wave limit of series and finding paicewise function  of Bij, which have a trick i don't know how reach is easy  but how reach that i don't know yet

@janhardo  i will ask in here each week maybe someone can figure out