taro

445 Reputation

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6 years, 100 days
Maple is to me difficult. The first version I bought was Maple9, and it was more than 15 years ago. But, I couldn't use it, feeling it too difficult. But, three years ago, I thought Maple might be helpful to my study, and since then, I have continued to learn Maple. As I got able to read the Maple help, I think that I could get to use maple better now than before. But, I feel that I am a beginner yet.

MaplePrimes Activity


These are replies submitted by taro

@nidojan 

I'm sorry. I think I might have lacked of enough explanation about my question.
What I want to do is to collect the part of -epsilon*z+z in a1 to z*(1-epsilon) in b1.

 

 

@Markiyan Hirnyk 

I think that your advice is to divide both of numerator and denominator with a specific expression. In that meaning, through doing so, I could simplify the expression which I wanted to simplify. Thank you.

 

@Kitonum 
Thank you for your teaching.
From your answer, I found substitution plays well.

Though a similar one, dividing first works well.

e1:=n = (theta-1)*(z-1)*(-k*psi*L*(-(epsilon-1)*psi/epsilon)^epsilon*k^epsilon+K*(-(epsilon-1)*psi*k/epsilon)^epsilon)/(gamma*((theta-1)*(z-1)*(-(epsilon-1)*psi*k/epsilon)^epsilon-(-(epsilon-1)*psi/epsilon)^epsilon*k^epsilon*theta*z*psi));
b:=(-(epsilon-1)*psi*k/epsilon)^epsilon;
c:=simplify(numer(rhs(e1))/b)/simplify(denom(rhs(e1))/b) assuming (k>0);

The problem in this case to me migh have been the use of assuming(k>0).

Thank you.

 

 

 @sand15 

Doesn't the way to ascertain whether all eigenvalues are positive become an answer?

Vector[row]([r,s]).Matrix([[1,-1/2],[-1/2,1]]).Vector[column]([r,s]);

expand(%)

a:=Matrix([[1,-1/2],[-1/2,1]]);

LinearAlgebra[Eigenvalues](a);

 

@Kitonum 

In my environment: maple2016, osx EL Capitan, the result of assignment is different from yours. A and B are reverse in my results. Could I ask you to show the way to correct this?

 

@Zeineb 

I think that what you want to obtain is the limit of g(t) when t goes to infinity.
Setting t=50, the following graph is drawn.

plot(abs(x^(2^(-50))-1),x=-0.1..2);

where it increases between -0.1 and 0, decreases between 0 and 1, and increases above 1.
I think you have to do is to show the part of below where.

By the way, how can I make that graph smooth?

 

@Kitonum 

Would you please tell me why "," that is comma, at the last of "evalindets(Expr, 'function', t->op(0, t)), " in yor code,
cannot be replaced with ";" that is semicolon?

 

 

@Scot Gould 

Sorry. As the description of two commands are the same other than the outcome of
examples there, I thought they were the same. But, they are different.
See below.

plot(-(x+2)*(x+1)*(x-1),x=-2.1..2.1);
evalf(ExtremePoints(-(x+2)*(x+1)*(x-1),x=-3..3));
evalf(CriticalPoints(-(x+2)*(x+1)*(x-1),x=-3..3));

The output of ExtremePoints contains the end points x=-3..3, and
that of CriticalPoints does not.
So, in the case of the original question, CriticalPoints, which is Markiyan's answer, is more appropriate.
 

@Scot Gould 

I think that I wrote the above anwer after reading mskalsi's question of
"I am interested in derivative. In fact my aim is to extract Maxima and Minima from plot."

As for the extreme points, the following which is  almost the same
as that of Markiyan Hirnyk, just different in the name, is my answer.

f:=0.012981+0.080285*cos(0.9519256799*x)+0.041370*cos(1.903851360*x)+
0.035690*cos(2.855777040*x)+0.000147*cos(3.807702720*x):

Student[Calculus1]:-ExtremePoints(f,x);
I don't know why two commands with the same function exist.
And, as for maximum of f,

Optimization[Maximize](f, x = -6 .. 6);
works.

 

Can you explain the meaning of your A_i B_{i j} = \sum_{i=1}^3 A_i B_{i j} in more detail with some conclete example?
And, please explain the meaning of your second expression of A_{i j} B_{m j} C_{i m} V_k.
From where did ,for example, the expression A_{i j} come from?


 

a:=-0.2126639710e-354*(-29.5456666e356*exp(-4.150297840*y)*cos(3.641492391*y));
       628.3298785 exp(-4.150297840 y) cos(3.641492391 y)
evalf(Int(a,y=-b..b));
    /b                                                        
   |                                                          
   |     628.3298785 exp(-4.150297840 y) cos(3.641492391 y) dy
   |                                                          
  /-1. b                                                      

The output of evalf(Int(a,y=-b..b)) cannot be evaluated to be numeric, because b is just a variable.

Maple 2016 is not assumed to work on Sierra.

http://www.maplesoft.com/products/system_requirements.aspx#maple

You have to wait for the next version of maple for its using in the Sierra.

 

@leonardofernandez 

Though this is not an answer to your question, I changed my setting of maple 2016 and mac osx 10.11.6
to Spanish setting, then I did what you did to get that eps.
As I cannot append the file with the extention eps to this site, I changed that extention to txt.
Can you open that file with double clicking after changing that extention of txt to eps?

By the way, I could open that file with my environment.

prueba.txt

 

 

@Rouben Rostamian  
Please write more explicitly for the function g.

 

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