graph a red bezier curve start at the point P1(0, 0, 1) in the direction of <-2, 0, 1> and ends at P3=(0, 2, 0) from the direction of <0, 1, 0>. Use "axes=normal" and rotate the image for a good view of the curve. Also, write the coordinates of the other two control points that you used.

http://math.stackexchange.com/questions/376240/how-to-calculate-grobner-basis-for-syzi-f1-f2-g1-g2

http://math.stackexchange.com/questions/376980/why-syz-algorithm-for-module-have-dimension-problem-how-to-divide-vector-and-mu

Hello,

for my mechanical engineering studies we have to optimize an engine during a workshop. Therefore we have to use a numerical dsolve to solve the equation of motion. I have to get the maximum bearing reaction for a constant rpm. In order to get this I can't think of anything else but use the dsolve solution and use it in maximize.

ysk_2 := t -> -rc*cos(phi(t))-lp*cos(alpha(t))-lkb-y(t);
ysp_2 := t -> -rc*cos(phi(t))-lp2*cos(alpha(t))-y(t);

I have a Mma code from a colleague that I am trying to port to Maple. This code uses a lot of Mma With[{...}, ...] constructs, to which I found the Maple "use ... in ... end use" construct the closest equivalent. What is being done is to initialize a bunch of local variables and then run the calculations. Non-initialized variables (the ones not in the first section) remain global.

I ran into a problem in Maple when I tried to initialize an element of a Vector, like "use a[1...

i'm using maple 15 and trying to solve the following PDE without success, can you help please.

(ab+(a*sin(x1))^2-(c*cos(x1))^2)*d/dx1(V(x1,x2))=-dsin(x1)/exp(x1).

where a,b,c and d are constants. and i need it to be solved as a PDE please.

thank you,

Mutaz

Hi,

My work requires me to use derivative a lot. Especially, the partial one. Given F(x,x_dot). Maple has this partial expression, however I'd like to partial differentiate F with regard to x_dot (the derivative of x over time).

Is this possible? If possible, please tell me how.

Thank you.

Abe

I was using the Finance package and used the command ImpliedVolatilitySurface(...). But it is showing the following error 
"Error, (in Finance:-ImpliedVolatilitySurface) external linking: error loading external library finance.dll: The specified module could not be found."Please help..

In geometry (2D), the triangle ABC has centroid is G(1, 1) and orthocenter is H(1,1). How to find the vertices A, B, C with the coordinates of this vertices are integers number?

what is the maple coding for the function, f(t)=-1-(epsilon)v(t) with the initial condition v(0)=1 for the 10 term?

i had did it but i don't know how to come up with the expansion series in the maple coding

i'm trying to solve this parametric parametequation(a1,a2 & l are parameters and n is my variable): 

a2*(l^(2*n)-1)-2*(a1+n*a2)*(l^n)*log(l)=0

when i try to solve this parametric equation, maple return a RootOf term and when i try to see the values of this RootOf by Allvalues, again return a RootOf, but when i replace the parameters by numbers(like a1=400, a2=25 & l=3.2), maple return a unique n. 

Helo every one,

I'm trying to find the positive real root from:

and substitute it in:

my prog is:

eq5:=u->-3*b*k*u^2-3*b*k^2*u^4-k^3*u^6*b+k*u+5*k^2*u^3-b:  

                   (solve(eq5(u),u)): S:=array([...

I am using Maple 15 and every time I try to plot this equation it doesnt seem to want to plot. This is the code I keep trying to input:

plot(3*e^(-x)*x-e^(-x)-1.5*e^(-x)*(x^2)+e^(-x)*(x^2)*log(x),x=0..9,y=-1..0.6);

Every time I get "Plotting Error, empty plot"

The equation came from the original differential equation .5(d^2y/dx^2)+(dy/dx)+.5y(x)=ln(x)e^(-x)

 Also When i try to plot this equation:

-.5*e^(-10*x)*sin(10*x)-.5*e^(-10*x)*cos(10*x)+(3/2)=300

I want to know how to take the fourier transform of a solution to an IVP obtained using dsolve/numeric and consequently plot the transform. any ideas?

Hi,

I am using the function simplify in order to simplify some big expressions I have. The poblem is:

I have the expression F=F(x1,x2,x3,......,xn)  and if I evaluate the two following expressions

expr1 = subs(x1=a, x2=b, x3 =c , .......,xn=d, F) = F1    (scalar)

expr2 = subs(x1=a, x2=b, x3 =c , .......,xn=d, simplify(F) ) = F2    (scalar)

Normally F1 and F2 are equal  ( F1=F2 ) but what I really get...