Congratulations to Eric Miles, a graduate teaching assistant at Colorado State University, for winning the second individual prize of The Möbius App Challenge! Eric will be receiving an iPad prize pack for his app Stretch and Translate Sin(x).

Maplesoft launched the Möbius App Challenge earlier this year to give Maplesoft community members the opportunity to get involved in the creation of Möbius Apps. This contest seeks to challenge users to create Math Apps using Maple, submit them to The Möbius Project website, then award the most useful, creative, and effective submissions. Finalists from the individual level challenge are chosen four times a year, so make sure to enter the next round of the challenge for your chance at a Maplesoft prize pack!

For full contest details and to enter, please visit: http://www.maplesoft.com/lp/mobius/index.aspx.

Jonny Zivku
Maplesoft Product Manager, Maple T.A.

I need to make a graph that has dates 1/14/2000 on the x axis and intrest rates on the y axis but when i import my spread sheet from excell the dates keep getting converted into lager numbers like 37000 for some reason and i cannot figure out how to stop this odd conversion. Has anyone encountered this?? i tried looking up dates in maple hepl but cant find much on this topic. Hope i explained what is happening well enough. Graph_One_b.mwGraph_One_b.mw

I have to solve a complex equation whose solutions, I'm looking for, are real numbers, I chose a command 'solve ' to solve this problem but the program shows me this message 'warning solutions May Have Lost'. How I can resolve this problem?

this is the equation and the message :

solve({((abs((((1-(nc-I*kc))/(1+(nc-I*kc)))+(((nc-I*kc)-(0.518-I*0.023))/((nc-I*kc)+(0.518-I*0.023)))*exp(-I*4*3.14*h*(nc-I*kc)/lamda))/(1+((1-(nc-I*kc))/(1+(nc-I*kc)))*(((nc-I*kc)-(0.518-I*0.023))/((nc-I*kc)+(0.518-I*0.023)))*exp(-I*4*3.14*2500*(nc-I*kc)/581))))^2)*100=43.12,((abs((((1-(nc-I*kc))/(1+(nc-I*kc)))+(((nc-I*kc)-(0.176-I*0.023))/((nc-I*kc)+(0.176-I*0.023)))*exp(-I*4*3.14*h*(nc-I*kc)/lamda))/(1+((1-(nc-I*kc))/(1+(nc-I*kc)))*(((nc-I*kc)-(0.176-I*0.023))/((nc-I*kc)+(0.176-I*0.023)))*exp(-I*4*3.14*2500*(nc-I*kc)/720))))^2)*100=44.37},{kc,nc});
{kc,nc};

Warning, solutions may have been lost            {kc, nc}

So I need a help .

Hi,

I have a system of equations for which I want to get a solution around an initial guess, unfortunatly I cannot succed it. Here is the system and the initial guess

solve({(-(((1/((0.005+0.009)^2+(0.072+1*(Ladssec+Ll))*(0.072+1*(Laqssec+Ll))))*((0.005+0.009)*sin(-0.785)+(0.072+1*(Ladssec+Ll))*cos(-0.785)))*((Ladssec*(-id0+(0.953/Lfd)+(0.849/L1d)))+Laqssec*id0)-((1/((0.005+0.009)^2+(0.072+1*(Ladssec+Ll))*(0.072+1*(Laqssec+Ll))))*((0.072+1*(Laqssec+Ll))*sin(-0.785)-(0.005+0.009)*cos(-0.785)))*((Laqssec*(-iq0+(0.468/L1q)))+Ladssec*iq0))/(2*2.5))=-1.7858
,(-((((0.005+0.009)/((0.005+0.009)^2+(0.072+1*(Ladssec+Ll))*(0.072+1*(Laqssec+Ll))))*(Ladssec/Lfd))*((Ladssec*(-id0+(0.953/Lfd)+(0.849/L1d)))+Laqssec*id0)-(((0.072+1*(Laqssec+Ll))*Ladssec)/(((0.005+0.009)^2+(0.072+1*(Ladssec+Ll))*(0.072+1*(Laqssec+Ll)))*Lfd))*((Laqssec*(-iq0+(0.468/L1q)))+Ladssec*iq0)+((Ladssec*iq0)/Lfd)) /(2*2.5))=0.1036
,(-((-((0.005+0.009)/((0.005+0.009)^2+(0.072+1*(Ladssec+Ll))*(0.072+1*(Laqssec+Ll))))*(Ladssec/L1d))*((Ladssec*(-id0+(0.953/Lfd)+(0.849/L1d)))+Laqssec*id0)-(((0.072+1*(Laqssec+Ll))*Ladssec)/(((0.005+0.009)^2+(0.072+1*(Ladssec+Ll))*(0.072+1*(Laqssec+Ll)))*L1d))*((Laqssec*(-iq0+(0.468/L1q)))+Ladssec*iq0)+((Ladssec*iq0)/L1d)) /(2*2.5))=0.2279
,(-((((0.072+1*(Ladssec+Ll))*Laqssec)/(((0.005+0.009)^2+(0.072+1*(Ladssec+Ll))*(0.072+1*(Laqssec+Ll)))*L1q))*((Ladssec*(-id0+(0.953/Lfd)+(0.849/L1d)))+Laqssec*id0)-(-((0.005+0.009)/((0.005+0.009)^2+(0.072+1*(Ladssec+Ll))*(0.072+1*(Laqssec+Ll))))*(Laqssec/L1q))*((Laqssec*(-iq0+(0.468/L1q)))+Ladssec*iq0)-((Laqssec*id0)/L1q)) /(2*2.5))=-2.3313

,(-(1*Rfd*((1/((0.005+0.009)^2+(0.072+1*(Ladssec+Ll))*(0.072+1*(Laqssec+Ll))))*((0.072+1*(Laqssec+Ll))*sin(-0.785)-(0.005+0.009)*cos(-0.785)))*Ladssec)/(Lfd))=0.0023
,(-(1*Rfd*(1-(Ladssec/Lfd)+((((0.072+1*(Laqssec+Ll))*Ladssec)/(((0.005+0.009)^2+(0.072+1*(Ladssec+Ll))*(0.072+1*(Laqssec+Ll)))*Lfd)) *Ladssec)))/(Lfd))=-0.0054
,(-(1*Rfd*(-(Ladssec/Lfd)+((((0.072+1*(Laqssec+Ll))*Ladssec)/(((0.005+0.009)^2+(0.072+1*(Ladssec+Ll))*(0.072+1*(Laqssec+Ll)))*L1d)) *Ladssec)))/(Lfd))= 0.0018
,(-(1*Rfd*(-((0.005+0.009)/((0.005+0.009)^2+(0.072+1*(Ladssec+Ll))*(0.072+1*(Laqssec+Ll))))*(Laqssec/L1q))*Ladssec)/(Lfd))=5.8369e-04

,(-(1*R1d*((1/((0.005+0.009)^2+(0.072+1*(Ladssec+Ll))*(0.072+1*(Laqssec+Ll))))*((0.072+1*(Laqssec+Ll))*sin(-0.785)-(0.005+0.009)*cos(-0.785)))*Ladssec)/(L1d))=0.1303
,(-(1*R1d*(-(Ladssec/Lfd)+((((0.072+1*(Laqssec+Ll))*Ladssec)/(((0.005+0.009)^2+(0.072+1*(Ladssec+Ll))*(0.072+1*(Laqssec+Ll)))*Lfd))*Ladssec)))/(L1d))=0.1157
,(-(1*R1d*(1-(Ladssec/Lfd)+((((0.072+1*(Laqssec+Ll))*Ladssec)/(((0.005+0.009)^2+(0.072+1*(Ladssec+Ll))*(0.072+1*(Laqssec+Ll)))*L1d)) *Ladssec)))/(L1d))= -0.3192
,(-(1*R1d*(-((0.005+0.009)/((0.005+0.009)^2+(0.072+1*(Ladssec+Ll))*(0.072+1*(Laqssec+Ll))))*(Laqssec/L1q))*Ladssec)/(L1d))=0.0333

,(-(1*R1q*((1/((0.005+0.009)^2+(0.072+1*(Ladssec+Ll))*(0.072+1*(Laqssec+Ll))))*((0.005+0.009)*sin(-0.785)+(0.072+1*(Ladssec+Ll))*cos(-0.785))) *Laqssec)/(L1q))=-0.1323
,(-(1*R1q*(((0.005+0.009)/((0.005+0.009)^2+(0.072+1*(Ladssec+Ll))*(0.072+1*(Laqssec+Ll))))*(Ladssec/Lfd))*Laqssec)/(L1q))=-0.0044
,(-(1*R1q*(-((0.005+0.009)/((0.005+0.009)^2+(0.072+1*(Ladssec+Ll))*(0.072+1*(Laqssec+Ll))))*(Ladssec/L1d))*Laqssec)/(L1q))= 0.0051
,(-(1*R1q*(1-(Laqssec/L1q)+((((0.072+1*(Ladssec+Ll))*Laqssec)/(((0.005+0.009)^2+(0.072+1*(Ladssec+Ll))*(0.072+1*(Laqssec+Ll)))*L1q))*Laqssec)))/(L1q))=-0.2349}, {L1d, L1q, Ladssec, Laqssec, Lfd, R1d, R1q, Rfd},useassumptions)

Lfd ~=0.233, R1d~=0.0848, L1d~=0.2, L1q~=-0.09, Ladssec~=0.099, Laqssec~=-0.1, Rfd~=0.00173, R1q~=0.0129

Dear Maple forum,

given A, B real numbers,

and after defining the recurrent sequence

x(0) = A

x(n) = 0.5* x(n-1)^3 + B

I would like to see a graphic of x(n) on the plane x(n) - n.

how could I implement in maple 16?

thank you for your help.

JeanJ

Dear sirs/madams,

I tried to use my MAPLE in a MacBook with a quiet large screen...however I see the letter sizes of my Maple16 very small (the same wiht the font size on input and ouput sheets..and everywhere)..

Is there some way to "see larger and bigger"?

Thanks for your attention,

JeanJV

So I have the energy of an ion at a several points in space, where the x and z coordinates have been varied from 0-1, keeping y constant. The data is in the following file: 

y=0.xlsx

When I come to produce a 3D surface plot (grid) of this file using the plots option in the context menu (on right clicking), the following is produced: the x-axis is in red and the y-axis (z-coordinate) is in blue.

Yet if I use the interactive plot builder, to plot the same data, the only option available to me is a 3D point plot, which produces the following:

[If I try to plot a 3D surface plot (points) using the context menu, I get stuck at a evaluating stage...]

as, ideally, I want a surface plot, why, in the surface plot (grid) is MAPLE not recognising the data that corresponds to the higher z-coordinate values and how I can produce a full surface plot... 

Hi, I just want to know if there is simulated annealing programming in maple 14 and where I can get that programming

Hi

 I have a problem why the result does not appear..my code are:

> P := array([[8, 4], [8, 3], [8, 2], [7, 1], [6, 0], [5, 0], [4, 0], [2, 1], [1, 1], [1, 4]]);

> for j from 2 to 5 do k[j] := j+1;

x[j] := add(P[j, 1], j = j-1 .. j+2);

X[j] := add(P[j, 1]^2, j = j-1 .. j+2);

y[j] := add(P[j, 2], j = j-1 .. j+2);

Y[j] := add(P[j, 2]^2, j = j-1 .. j+2);

xy[j] := add(P[j, 1]*P[j, 2], j = j-1 .. j+2);

cx[j] := evalf(x[j]/k[j]);

cy[j] := evalf(y[j]/k[j]);

c11[j] := evalf(X[j]/k[j]-cx[j]^2);

c22[j] := evalf(Y[j]/k[j]-cy[j]^2);

c12[j] := evalf(xy[j]/k[j]-cx[j]*cy[j]);

C[j] := evalf(Matrix(2, 2, [[c11[j], c12[j]], [c12[j], c22[j]]]));

E[j] := Eigenvalues(C[j]);

if E[j][1] > E[j][2] then lambda[j] := E[j][2]/(E[j][1]+E[j][2]) else lambda[j] := E[j][1]/(E[j][1]+E[j][2])

end if;

end do;

the If function does not work and the result does not appear. Is there any problem in my code.

 Thanks

I was asked to transform (x+y)^2+(1)/x+y into ((x+y)^3+1)/x+y, I have tried nomer/denom, but i don't how to factorise the nomer bit into (x+y)^3+1 because maple factorise it differently by default. therefore, it would be grateful if anyone can help me with this...please?

I am trying to run the application "The Cosmic Travel Planner" by Christian Bar (CBaer), uploaded on August 21, 2013 on Maple cloud (Mobius@admin). I use the left panel of GUI where "MapleCloud" is opened. While opening the application GUI asks my permission for running some code automatically. After my 'YES' Maple gives me an error:

Startup Code Error
0, "permission denied: no read access (%1)", "C:\Users\Andriy\MapleLib"

I tried to give the permission to folder "C:\Users\Andriy\MapleLib" however unsuccessfuly.

OS: Win 8

Could you help me with this Error? Thank you.

I have an equation x²y-3y³x=0. I want to find the slope of the graph at the point (3,1) , that is the derivative at that point. I was told it was possible to do this in one line of command, so I was just wondering if anyone knoew how to do this. Any ideas would be helpful. Thanks in advance.

Hi

I have entered two functions and got a solotion for them:

Now i want to know if there is someway Maple can do this automaticly:

So that i not have to do like i did here, manuel copy-paste the values into the function, or re-enter them.

Using Maple 17.02 on Windows 64-bit, but i guess that makes no differance, since it's java :) 

Try makeing it simple, i'm new with Maple.

Thanks in advance!

Emil Kristensen

PDE.mw

Hi i attach the file that i have problem with.I guess it is not the first problem with datatype=float[8], but i will appreciate if someone could help me with it.

After calling pdsolve i get the answer in the module "structure", i try to plot it and i get :

Error, (in pdsolve/numeric/plot) unable to compute solution for t<HFloat(0.0):
unable to store [.02091392039809]-5.00000000000000 when datatype=float[8]

I am not sure how to interpret it and what should i change to make it work.

My PDE is a Bellman equation and my problem is that i actually know only one boundary condition "icond", is there a way to solve it without other conditions?

Thank you

I gave this function:

g := -2-k[1](lambda*alpha[2]*k[2]+alpha[1](-2-2*k[2]+k[2]*lambda^2))+k[1](lambda*alpha[2]*k[2]+alpha[1](-2-2*k[2]+k[2]*lambda^2))*lambda(lambda*alpha[2]*k[2]+alpha[1](-2-2*k[2]+k[2]*lambda^2))^2

I would like to factor out or to collect:   (lambda*alpha[2]*k[2]+alpha[1](-2-2*k[2]+k[2]*lambda^2))

I use following command: collect(g, lambda*alpha[2]*k[2]+alpha[1](-2-2*k[2]+k[2]*lambda^2))

Nevertheless, I receive an error ...

Error, (in collect) cannot collect lambda*alpha[2]*k[2]+alpha[1](-2-2*k[2]+k[2]*lambda^2)

Could you help me to solve my issue ? 

What am I doing wrong ? Do I have to use another command for this ?

I would like to thank you in advance.

Best regards,

D.L.