I have tried the Physics package. First of all, how can I define a non-ortogonal basis (using kets)? Suppose I have a basis formed by linearly independt vectors. How to set them non-ortogonal?

Using plot3d I can obtain a plot of a function u:=f(x,y). Then I rotate the plot and find the view that I want by trial and error. However, If I run the plot again with different parameters, I have to again find the view I want by trial and error. Setting the plot3d orientation option by trial and error to achieve the required view is very tedious. My question is: Once I have found the view I like, is it possible to then obtain the orientation data so that it can be used in subsequent calls to plot3d? Any help appreciated.

Hi there, in this post http://www.mapleprimes.com/forum/howplot1 I asked one plotting question when Y[1] and Y[2] are independent what if they are not independnt? say I have f( y1, y2) for Y[1] in [a,b] and Y[2] in[c,d] then I have U[1] = f ( Y[1], Y[2] ) and U[2] f ( Y[1], Y[2] ) (different functions of Y[1] and Y[2]) How do I plot the mapping for U[1] and U[2]? to determine the range for u1 and u2? Thanks Casper =============================

Hi everyone!

I'm stuck with a problem, and I thought I might get some help here. Would be greatly appreciated. Anyway, here goes:

For a given function of two variables, say g(x,y), we can produce a 2d-contourplot (for example using the contourplot-command). No that's all swell as long as we actually have a closed expression for our function g (like, for example, sin(x^2 + y)).

Hi there, here are the commands: > y[1]:=exp(1)^(-(1/2)*(u[1]^2+u[2]^2)); > y[2]:=arctan(u[2]/u[1])/(2*Pi); > a:=diff(y[1],u[1]);b:=diff(y[1],u[2]);c:=diff(y[2],u[1]);d:=diff(y[2],u[2]); then it begins > a*d-c*b; g:=abs(simplify(%)); i got the funny "Re" thing in the expression why it didnt give me the answer as I would expected if I use the following command? > a*d-c*b; g:=-1*simplify(%); that's what I wanted the idea is I want the absolute value of the simplified answer ( simpify(%)) what's the difference here?

convert( (z)_n, GAMMA)  does not give the desired  GAMMA(z+n)/GAMMA(z).

Instead of Maple gives the answer   (z)_n.

How could I obtain the GAMMA form?

Thanks,

                   Sandor

Hi, I got to several funtions as follows: U[1]:= ( -2 * ln(Y[1]) )^(1/2) * cos(2*Pi* Y[2]) U[2]:= ( -2 * ln(Y[1]) )^(1/2) * sin(2*Pi* Y[2]) for Y[1] and Y[2] in (0,1) I want to find the range for U[1] andU[2] how do I plot them? Thanks Casper

In Maple11 odeadvisor does not know the Euler type differential equation.

For example, R(r)+ r R'(r)+r^2 R''(r)=0.

It is the same situation in Maple12?

Thanks, Sandor

My question is in the worksheet attached to this document.   Thank you, trinity  

Hey everybody!

First of all I want to say hallo, since this is my firstpost in this forum :-).

I really enjoy working with maple, however, I have run into trouble trying to solve an integral for a mean value.

During project work at university, we have to design a water rocket. For the design, it is crucial to know the mean thrust that is produced by the water that is exiting the bottle.

Hello! Sorry for my bad english. I have question: How do I solve non-linear otimal control problem in Maple (my version of program is 11)? I interesting in numeric result, non symbolyc. Standart tools didn't solve my problem. Please give my link for maple worksheets or other information on this topic. Thank you!

Hi my dear friends,

I’ve developed a simple procedure as follows:

I can simulate first order autocorrelation as

restart;
with(Statistics);
randomize();
n := 1000;
p := 0.9;
r := Sample(RandomVariable(Normal(0, 1)), n);
for i from 2 to n do
x[1] := 0;
x[i] := p*x[i-1]+r[i] end do;
rr := [seq(x[i], i = 1 .. n)];
Correlation(rr[1 .. nops(rr)-1], rr[2 .. nops(rr)])

 

I can simulate second order autocorrelation as

<p>Hello</p>
<p>I'm a beginner and I need to implement this recursive function with Maple:</p>
<p>$$\left\{\begin{array}{c}<br />
Z(1)=(1-p_a)(1-p_b)\\<br />
Z(i)=((1-p_a)(1-p_b))^{\left(\frac{p_a}{1-p_a}+\frac{p_b}{1-p_b}\right)^i}\prod_{k=1}^{i-1}(1-Z(k))<br />
\end{array}\right.$$</p>
<p>where 0<p_a<1 and 0<p_b<1</p>
<p>So I write in Maple:</p>
<p>Z:=(i, pa, pb)->if i=1 then (1-pa)*(1-pb) else (((1-pa)*(1-pb))^((pa/(1-pa)+pb/(1-pb))^i))*product(1-Z(k, pa, pb),k=1..i-1) end if;</p>
<p>When i=1 the function works</p>