sorry , i forget the term so the question is :

int ( q  * exp((1-b)^2* q_z^2 / lambda[1] ) * exp((1-b)^2* q^2 / lambda[2])   /  ((1+b^2*q^2+b^2*q_z^2)*(q^2+q_z^2)) , q_z= -infinity..infinity)  then w.r.t     q  from (0......infinity)

after integration we want to minimize the results , the range is as (b=0..1), ( lambda[1])  =1....100000) ,   (lambda[2])  =1....100000)

Hello,

I need some help to figure out how to get maple to use distributive property and rules of exponents.

>A:=R/(1+exp(-2(h-s))

>a:=A/(exp(h-s))

I would like to get the answer back in the form

R/(exp(h-s)+exp(-(h-s))

suggestions?

I have this line in maple 11:

polygonplot([[0,0],[1,1],[1,0],[0,0]],legend="stuff");

and the legend doesn't appear, is there a way to force maple to produce the legend (other than horribly right clicking and manually writing the legend in every time - I'm trying to make lots of polygon plots...)

thanks

Steve

Hello everyone,

I'm trying to solve a largeish matrix equation of the form A*X + Transpose(A*X) = B for X, where A and B are known matrices.  I know there must be some clever way to get Maple to automatically unpack this equation into the equations for the components and then solve them symbolically, but I haven't had much success.  Could someone more skilled point the way?

Thanks.

Hello,

Using Maple, I integrated and expression and got ln(e) in the answer.  How can I eliminate this?

Thanks

i have this integration:

int(q*exp((1-b)^2* q_z^2/lambda )/((1+b^2*q^2+b^2*q_z^2)*(q^2+q_z^2)),q_z=-infinity..infinity) then w.r.t      q  from (0......infinity)

I want to take two numbers, for example 37665432 and 59374696 (later extrapolate to 3 or 4 etc... sets of numbers) and take each individual number alternately and put them into a list. 

Here's what I have

a:=37665432;

b:=59374696;

c:=convert(a,base,10);

d:=convert(b,base,10);

e:=ListTools:-Reverse(c);

f:=ListTools:-Reverse(d);

So now I have the numbers all in a list and I want to select each one alternately into another list.

g:=seq(e[i],f[i],i=1..8); 

I am going to simplify the following formula:

sqrt(a^2*p*(1-p)*(N-n)/(n^2*(N-1)))

I wrote simplify(sqrt(a^2*p*(1-p)*(N-n)/(n^2*(N-1))),symbolic), the output was:

Hi,

I have a series solution to a differential equation. The recurrence relation is such that knowing the first four coefficients is sufficient to determine all the other coefficients. Now I want to represent this solution in terms of f(x)*c0+g(x)*c1+h(x)*c2+k(x)*c3 where f,g,h,k are all polynomials in x. I tried searching for commands related to simplify, but I was unable to solve my problem. 

p.s : i am not aware if this has already been discussed so please bear with me

Hello,

I am having trouble with posing an integration for the following function, wrt z.

u:= sin (theta)  * ((s^2 + z^2)/2 +h*z)

I want to be able to change the values of h, s, and theta.

I would like to integrate u, wrt z, from s to h.

I have tried the basics, such as....

int(u, z)   and

int(u, z=s..h)

I get the integrand symbol and a general setup but I am not posing it clearly enough to get Maple to perform the integration.

Thanks for any help you can offer.

I have a procedure that I use frequently. I tried to include this procedure in other Maple sessions so that I can reuse that procudure. I tried the command $include but received the following error message:

$include "c:/myworks/myplot.wm"

Error, unexpected string
 

where myplot.wm is a file that contains a procedure which I want use repeatedly.  What is wrong there?

Thanks.

assume(u::real)

assume(v>0)

assume(lambda>0)

Im( u+i v / u+i v+lambda )   is ok.

Im( (u+i v / u+i v+lambda)^2 )   is ok.

Im( (u+i v / u+i v+lambda)^3 )   is ok.

Im( (u+i v / u+i v+lambda)^4 )   is not ok.

Maple gives back the input.  

What is the problem with my input?

Sandor

Hi,

I need some help.  I have a system of ODE's subject to a system of Boundary Conditions.  I can't figure out the sequence of commands to get MAPLE to generate a solution.

ODE System:

SYS1 := {diff((C[10])(z), `$`(z, 2)) = (BR[1]+BR[2])*(C[10])(z)-BR[3]-(BR[4]+BR[5])*C[50], diff((C[51])(z), `$`(z, 2)) = Ped*u[0]*C[50*x]-BR[5]*(C[10])(z)+BR[3]*C[50]}

Boundary Conditions:  I am going to be evaluating from z=s to z=h

BC1 := {(C[10])(h) = 1, diff((C[10])(s), s) = 0, diff((C[51])(h), h) = 0, diff((C[51])(s), s) = Da[1]*(C[50]-J3)}