Plot the first 20 Fibonacci numbers.

I have this so far..

restart;

nums := [seq(i, i = 1 .. 20)]*with(combinat, fibonacci);

fibnums;

  here my loop; after  8 iteration maple couldnt solve the equations and give me this error .
Is there any method to garentee that fsolve could work intire the 1000 iteration 
 

I am calling a function (GTS2) multiple times with varying inputs, using the curry function, and i want to record how long/how much RAM the function takes with each input, and put those in seperate matrices that i can plot later
 

Sols3 := proc (H::algebraic, F::(list(algebraic)), i::posint, j::posint) options operator, arrow; GTS2(H, F, i, j) end proc;
n, m := 5, 4;
M=Matrix(n, m, curry(Sols3, H, F))

You can find all the functions required in this worksheet. The curried call to this function is in section 4.

MHD_cchf_2.mw
 

Download MHD_cchf_2.mw

Respected sir, I try to plot graphs using two parameters once. But it showing the error as

Error, invalid input: nops expects 1 argument, but received 2
Error, invalid input: nops expects 1 argument, but received 2
Error, invalid input: nops expects 1 argument, but received 2

can anybody do help in this regard?

I have a problem writing a program for the numerical solution of nonlinear volterra integral equation using the method of reproducing kernel space. I have my algorithm as well as the program I tried to write, though they are full of error messages. Please could anyone give me a clue on how to go about my challenges. The algorithm is as follows:

Step 1. Fix 𝑎 ≤ 𝑥 and 𝑡 ≤ 𝑏.
If 𝑡 ≤ 𝑥, set 𝑅𝑥(𝑡) = 1 − 𝑎 + 𝑡.
Else set 𝑅𝑥(𝑡) = 1 − 𝑎 + 𝑥.
Step 2. For 𝑖 = 1, 2, . . . , 𝑚 set 𝑥_i = (𝑖 − 1)/(𝑚 − 1).

Set 𝜓_i(𝑥) = 𝐿_t𝑅𝑥(𝑡)|𝑡=𝑥_i .
Step 3. Set 𝑢₀(𝑥₁) = 𝑢(𝑥₁).
Step 4. For 𝑖 = 1, 2, . . . , 𝑚 set 𝛾_ij = [𝜓^-1]_ij.
Step 5. 𝑛 = 1.
Step 6. Set S_n = Σ𝑛
𝑘=1 𝛾_nk𝑢_k-1(𝑥_k).
Step 7. Set 𝑢_n(𝑥) = Σ𝑛
𝑖=1 S_i𝜓_i(𝑥).
Step 8. If 𝑛 < 𝑚then set 𝑛 = 𝑛 + 1 and go to step 6.
Else stop.

how can i plot outside of an sphere? for example x^2+y^2+z^2>1 ? tnx for help

So I have this system of equations with which I am not sure if the result is the same or not using "series" and "limit" or what is going on here.

I hope it is clear what I mean.

Download Mapleprimes_-_Ionproduct.mw

restart;
N:=4;alpha:=5*3.14/180;r:=10;Ha:=5;H:=1;
dsolve(diff(f(x),x,x,x));
Rf:=diff(f[m-1](x),x,x,x)+2*alpha*r*sum*(f[m-1-n](x)*diff(f[n](x),x),n=0..m-1)
+(4-Ha)*(alpha)^2*diff(f[m-1](x),x);
dsolve(diff(f[m](x),x,x,x)-CHI[m]*(diff(f[m-1](x),x,x,x))=h*H*Rf,f[m](x));
f[0](x):=1-x^2;
for m from 1 by 1 to N do
CHI[m]:='if'(m>1,1,0);
f[m](x):=int(int(int(CHI[m]*(diff(f[m-1](x),x,x,x))+h*H(diff(f[m-1](x),x,x,x))
+2*h*H*alpha*r*(sum(f[m-1-n](x)*(diff(f[n](x),x)),n=0..m-1))+4*h*H*alpha^2*
(diff(f[m-1](x),x))-h*H*alpha^2*(diff(f[m-1](x),x))*Ha,x),x)+_C1*x,x)+_C2*x+_C3;
s1:=evalf(subs(x=0,f[m](x)))=0;
s2:=evalf(subs(x=0,diff(f[m](x),x)))=0;
s1:=evalf(subs(x=1,f[m](x)))=0;
s:={s1,s2,s3}:
f[m](x):=simplify(subs(solve(s,{_C1,_C2,_C3}),f[m](x)));
end do;
f(x):=sum(f[1](x),1=0..N);
hh:=evalf(subs(x=1,diff(f(x),x))):
plot(hh,h=-1.5..-0.2);
A(x):=subs(h=-0.9,f(x));
plot(A(x),x=0..1);

A parameterization of the function i am studying this morning produced what seems to be not single valued on the domain i choose,

plot(floor((x+1)^2/x^2)-(x+1)^2, x = -10 .. 10, coords = logarithmic);

plot(floor((x+1)^2/x^2)-(x+1)^2, x = -10 .. 10, coords = logcosh);

but the cartesian is fine:

Dear Users!

I am facing problem to compare the coefficient of x^i*y^j for i, j =1..,Equations. Please my effort and fix the problem.

H1 := 3*y^4*a[1]^5*b[1]+6*y^4*a[1]^3*b[1]^3+3*y^4*a[1]*b[1]^5+6*x*y^3*a[1]^5+6*x*y^3*a[1]^4*b[1]+12*x*y^3*a[1]^3*b[1]^2+12*x*y^3*a[1]^2*b[1]^3+6*x*y^3*a[1]*b[1]^4+6*x*y^3*b[1]^5+6*y^3*a[1]^5*b[2]+6*y^3*a[1]^4*a[2]*b[1]+12*y^3*a[1]^3*b[1]^2*b[2]+12*y^3*a[1]^2*a[2]*b[1]^3+6*y^3*a[1]*b[1]^4*b[2]+6*y^3*a[2]*b[1]^5+18*x^2*y^2*a[1]^4+36*x^2*y^2*a[1]^2*b[1]^2+18*x^2*y^2*b[1]^4+18*x*y^2*a[1]^4*a[2]+18*x*y^2*a[1]^4*b[2]+36*x*y^2*a[1]^2*a[2]*b[1]^2+36*x*y^2*a[1]^2*b[1]^2*b[2]+18*x*y^2*a[2]*b[1]^4+18*x*y^2*b[1]^4*b[2]+18*y^2*a[1]^4*a[2]*b[2]+36*y^2*a[1]^2*a[2]*b[1]^2*b[2]+18*y^2*a[2]*b[1]^4*b[2]-5*delta*y^2*a[1]^4-8*delta*y^2*a[1]^3*b[1]-10*delta*y^2*a[1]^2*b[1]^2-8*delta*y^2*a[1]*b[1]^3-5*delta*y^2*b[1]^4+12*x^3*y*a[1]^3+12*x^3*y*a[1]^2*b[1]+12*x^3*y*a[1]*b[1]^2+12*x^3*y*b[1]^3+36*x^2*y*a[1]^3*a[2]+36*x^2*y*a[1]^2*b[1]*b[2]+36*x^2*y*a[1]*a[2]*b[1]^2+36*x^2*y*b[1]^3*b[2]+18*x*y*a[1]^3*a[2]^2+36*x*y*a[1]^3*a[2]*b[2]-18*x*y*a[1]^3*b[2]^2-18*x*y*a[1]^2*a[2]^2*b[1]+36*x*y*a[1]^2*a[2]*b[1]*b[2]+18*x*y*a[1]^2*b[1]*b[2]^2+18*x*y*a[1]*a[2]^2*b[1]^2+36*x*y*a[1]*a[2]*b[1]^2*b[2]-18*x*y*a[1]*b[1]^2*b[2]^2-18*x*y*a[2]^2*b[1]^3+36*x*y*a[2]*b[1]^3*b[2]+18*x*y*b[1]^3*b[2]^2+18*y*a[1]^3*a[2]^2*b[2]-6*y*a[1]^3*b[2]^3-6*y*a[1]^2*a[2]^3*b[1]+18*y*a[1]^2*a[2]*b[1]*b[2]^2+18*y*a[1]*a[2]^2*b[1]^2*b[2]-6*y*a[1]*b[1]^2*b[2]^3-6*y*a[2]^3*b[1]^3+18*y*a[2]*b[1]^3*b[2]^2-16*delta*x*y*a[1]^3-20*delta*x*y*a[1]^2*b[1]-20*delta*x*y*a[1]*b[1]^2-16*delta*x*y*b[1]^3-10*delta*y*a[1]^3*a[2]-6*delta*y*a[1]^3*b[2]-10*delta*y*a[1]^2*a[2]*b[1]-10*delta*y*a[1]^2*b[1]*b[2]-10*delta*y*a[1]*a[2]*b[1]^2-10*delta*y*a[1]*b[1]^2*b[2]-6*delta*y*a[2]*b[1]^3-10*delta*y*b[1]^3*b[2]+12*x^4*a[1]*b[1]+12*x^3*a[1]^2*a[2]-12*x^3*a[1]^2*b[2]+24*x^3*a[1]*a[2]*b[1]+24*x^3*a[1]*b[1]*b[2]-12*x^3*a[2]*b[1]^2+12*x^3*b[1]^2*b[2]+18*x^2*a[1]^2*a[2]^2-18*x^2*a[1]^2*b[2]^2+72*x^2*a[1]*a[2]*b[1]*b[2]-18*x^2*a[2]^2*b[1]^2+18*x^2*b[1]^2*b[2]^2+6*x*a[1]^2*a[2]^3+18*x*a[1]^2*a[2]^2*b[2]-18*x*a[1]^2*a[2]*b[2]^2-6*x*a[1]^2*b[2]^3-12*x*a[1]*a[2]^3*b[1]+36*x*a[1]*a[2]^2*b[1]*b[2]+36*x*a[1]*a[2]*b[1]*b[2]^2-12*x*a[1]*b[1]*b[2]^3-6*x*a[2]^3*b[1]^2-18*x*a[2]^2*b[1]^2*b[2]+18*x*a[2]*b[1]^2*b[2]^2+6*x*b[1]^2*b[2]^3+6*a[1]^2*a[2]^3*b[2]-6*a[1]^2*a[2]*b[2]^3-3*a[1]*a[2]^4*b[1]+18*a[1]*a[2]^2*b[1]*b[2]^2-3*a[1]*b[1]*b[2]^4-6*a[2]^3*b[1]^2*b[2]+6*a[2]*b[1]^2*b[2]^3-10*delta*x^2*a[1]^2-16*delta*x^2*a[1]*b[1]-10*delta*x^2*b[1]^2-16*delta*x*a[1]^2*a[2]-4*delta*x*a[1]^2*b[2]-16*delta*x*a[1]*a[2]*b[1]-16*delta*x*a[1]*b[1]*b[2]-4*delta*x*a[2]*b[1]^2-16*delta*x*b[1]^2*b[2]-5*delta*a[1]^2*a[2]^2-6*delta*a[1]^2*a[2]*b[2]+delta*a[1]^2*b[2]^2-2*delta*a[1]*a[2]^2*b[1]-12*delta*a[1]*a[2]*b[1]*b[2]-2*delta*a[1]*b[1]*b[2]^2+delta*a[2]^2*b[1]^2-6*delta*a[2]*b[1]^2*b[2]-5*delta*b[1]^2*b[2]^2+delta^2*a[1]^2+delta^2*a[1]*b[1]+delta^2*b[1]^2+16*y^2*a[1]^2+48*y^2*a[1]*b[1]+16*y^2*b[1]^2+80*x*y*a[1]+80*x*y*b[1]+32*y*a[1]*a[2]+48*y*a[1]*b[2]+48*y*a[2]*b[1]+32*y*b[1]*b[2]+80*x^2+80*x*a[2]+80*x*b[2]+16*a[2]^2+48*a[2]*b[2]+16*b[2]^2-8*delta;

Equation := 12;

for i from 0 to Equation do;

for j from 0 to Equation do;

C[i, j] := coeff(H1, x^i*y^j) = 0;

end do;

end do;

I got this error
Error, invalid input: coeff received 1, which is not valid for its 2nd argument, x
 

Dear Users!

Hope you would be fine. I want to write an expression in sigma notation which control ny n (any constant >0);
for n =1 expression expand as

E[1]+1

for n =2 expression expand as
E[1]*E[2]*a[12]+E[1]+E[2]+1;

for n =3 expression expand as

E[1]*E[2]*E[3]*a[123]+E[1]*E[2]*a[12]+E[1]*E[3]*a[13]+E[2]*E[3]*a[23]+E[1]+E[2]+E[3]+1;

for n =4 expression expand as

E[1]*E[2]*E[3]*E[4]*c[1234]+E[1]*E[2]*E[3]*a[123]+E[1]*E[2]*E[4]*a[124]+E[1]*E[3]*E[4]*a[134]+E[2]*E[3]*E[4]*a[234]+E[1]*E[2]*a[12]+E[1]*E[3]*a[13]+E[1]*E[4]*a[14]+E[2]*E[3]*a[23]+E[2]*E[4]*a[24]+E[3]*E[4]*a[34]+E[1]+E[2]+E[3]+E[4]+1;

and so on.

I am waiting your kind respons. Thanks

Hello,

how to calculate the laplace transform for the following equations?

L1:=laplace(psi1(t)*(diff(z1(t), t)), t, s):
L2:=laplace((diff(psi1(t), t))^2, t, s):

I can't final an equivalent to Mathematica's Flatten for sets. I know Maple has ListTools:-Flatten for lists.   

For example, given set r:={a,{b,c},d,{e,f,{g,h}}}; How to convert it to  {a,b,c,d,e,f,g,h}; 

does one have to convert each set and all the inner sets to lists, then apply ListTools:-Flatten to the result? How to map convert(z,list) for all levels?

     map(z->convert(z,list),r);

does not work, since it only maps at top level, giving {[a], [d], [b, c], [e, f, {g, h}]}

So doing

   ListTools:-Flatten(convert(map(z->convert(z,list),r),list));

Gives [a, d, b, c, e, f, {g, h}] 

Hey there, I'm trying to count how many letter arrangements are possible by using the algorithm below (for Maple TA). It's a bit crude but the console tells me countcharacteroccurences second argument must be a string, but it works for the earlier letters. Can someone please give me a bit of guidance?

$temp = maple("
randomize();
with(MathML):
with(StringTools):
with(combinat):

rintS := rand(1..27);
word := ARITHMETIC,ALGORITHM,ASYMPTOTE,AVERAGE,CARTESIAN,CALCULUS,COEFFICIENT,COORDINATE,NUMERATOR,
DENOMINATOR,DIFFERENTIATE,DERIVATIVE,DIAMETER,DYNAMICS,EXTRAPOLATION,FACTORIALS,GEOMETRIC,
HYPOTENUSE,INTEGRATION,IRRATIONAL,INVERSE,ITERATION,POLYNOMIAL,COMBINATIONS,PERMUTATIONS,POLYGON;

disp := word[rintS()];
n := length(disp);

n1 := CountCharacterOccurrences(disp,A);
n2 := CountCharacterOccurrences(disp,B);
n3 := CountCharacterOccurrences(disp,C);
n4 := CountCharacterOccurrences(disp,D);
n5 := CountCharacterOccurrences(disp,E);
n6 := CountCharacterOccurrences(disp,F);
n7 := CountCharacterOccurrences(disp,G);
n8 := CountCharacterOccurrences(disp,H);
n9 := CountCharacterOccurrences(disp,I);
a1 := CountCharacterOccurrences(disp,J);
a2 := CountCharacterOccurrences(disp,K);
a3 := CountCharacterOccurrences(disp,L);
a4 := CountCharacterOccurrences(disp,M);
a5 := CountCharacterOccurrences(disp,N);
a6 := CountCharacterOccurrences(disp,O);
a7 := CountCharacterOccurrences(disp,P);
a8 := CountCharacterOccurrences(disp,Q);
a9 := CountCharacterOccurrences(disp,R);
b1 := CountCharacterOccurrences(disp,S);
b2 := CountCharacterOccurrences(disp,T);
b3 := CountCharacterOccurrences(disp,U);
b4 := CountCharacterOccurrences(disp,V);
b5 := CountCharacterOccurrences(disp,W);
b6 := CountCharacterOccurrences(disp,X);
b7 := CountCharacterOccurrences(disp,Y);
b8 := CountCharacterOccurrences(disp,Z);

z1 := n1!*n2!*n3!*n4!*n5!*n6!*n7!*n8!*n9!;
z2 := a1!*a2!*a3!*a4!*a5!*a6!*a7!*a8!*a9!;
z3 := b1!*b2!*b3!*b4!*b5!*b6!*b7!*b8!;
ans := n!/(z1*z2*z3);

Export(disp),convert(ans,string),convert(z1,string),convert(z2,string),convert(z3,string);
");

$ans = switch(1,$temp);
$disp = switch(0,$temp);