It exist some way to factorize with "restrictions"...

Given an algebraic expression p(x,y)..it is possible to factorize assuming that some terms are involved?. For example if I have poly1 and I expand it, I obtain a poly2 (with several terms).. now, if I factor(poly3) I dont recover the exact expression poly1. But at least in this case, it would be possible to factorize (or collect) poly3 asumming that in numerator and denominator we have the term(x+y)?. Thanks in advance, JJacques. poly1:= ((1-x-y)^2+ (2+x+y)^3)/((1+x+y)^2+ (4-x-y)^2); poly2:= expand(%); poly3:=factor(%);

Is "assume" or is "is" the reason?...

Hi, I cannot understand why IS fails below. Am I doing something wrong?. Maybe I generated a new variable when I wrote 2*L/(1-x-y).. Thanks a lot for reading this message, > restart; > assume(L=1/2); > assume(x>0,y>0); > additionally(x+y <> is(x <>"true" > is(2*L/(1-x-y)<>"FAILS" JJacques,

solving nonlinear equations...

can i use maple to solve 15 nonlinear equations in 15 unknowns in the following form: T1^2 + 5(T1T2) + 6(T1T3)+ 8 (T1T4) + 7 (T1T5) + ....... -5 (T1T15) = 0 T2^2 + 3(T2T1) + 6(T2T3) -3 (T2T4) + 5 (T2T5) + ....... -3 (T2T15) - (T1T3) = 0 where T1 + T2 + T3 + T4 + ... + T15 =1

Customizing the LaTeX output......

does somebody know how to tell maple to produce "a nicer" latex output? For example in workspace I get a nice fraction > y:=1/(1-x); y:=1/(1-x); but the latex command returns > latex(y); \left( 1-x \right) ^{-1}  I would like it to be something like \frac{1}{1-x}. My idea is that if maple knows how to print this as a fraction in the workspace, then the latex command could also behave like that. Any idea? Thanks in advance Jan

Generating a list.....

Hello Maple experts. How could I generate a way to obtain the lists (Ws) for an arbitrary m (integer +)? (Below I ilustrate for m=1,2 and 3). Probably it is needed to use "apply" and "map".. but I don't see how to do it. #If m:=1, I want to generate the #following list: >W1:= [seq([B(j1)], j1=0..1)]; # the output --> [[B(0)], [B(1)]] #If m:=2, I want to generate the #following list: >W2:= [seq(seq([B(j1,j2)],j1=0..1),j2=0..1)]; #output-> [[B(0, 0)], [B(1, 0)], [B(0, 1)], [B(1, 1)]] #If m:=3, I want to generate the #following list: >W3:= [seq(seq(seq([B(j1,j2,j3)], j1=0..1),j2=0..1),j3=0..1)];

Who are the "Other" mathematicians...

Out of curiosity, can those of you who voted "Other" in the current Greatest Mathematician poll share with us who you would have like to have seen? There are 8 of you who voted "Other". T4.

Version Problem...

I have a procedure that will run fine in Maple 8 but gives an error when it is run in Maple 9.5. The error is a "cannot solve error". Are there any known issues that may lead to this type of problem? Thanks.

Rearranging polynomials...

Is there an automatic command (or maybe it is needed a procedure) to rewrite (n+2 -k) * (n+1-k) as (n+2)*(n+1)k^0- (2n+3)*k^1 + k^2 ? Any suggestion will be very useful. Thanks in advance JJaques.

I am looking for the JavaDoc of com.maplesoft.openmaple.* -- is it available somewhere? It looks like the API allows me to do DAG-based calls to Maple, but parts of that API appear undocumented :-( I am working with some people in Ireland who would prefer to pass Maple DAGs rather than strings, and it sure looks like the API allows it, but it isn't fully documented. Help!

Just a variable...

Dear all: To point: It is possible to build a variable where I can have control of 4 groups of index around the variable, how i show above. G_INDEX1 G_INDEX2 VARIABLE G_INDEX3 G_INDEX4 I apreciate very much your help. best regards JADO

Imaginary part that (in theory) shouldn't be there...

Just a short question - I tried isolating U(t) below. The paper I got this from didn't give what U would be, but there shouldn't be an imaginary part - I forget what command/assumptions to use in order to get rid of it. I've attached the rest of my worksheet in case anyone wants to see it - the parameters I used in param1 were given in the paper.

e1 := 30 = (0.19e-1*exp(2.5588*U(t))+0.518e-1*exp(2.6788*U(t)))*U(t);

graphing a second order differential...

I'm trying to graph this differential f''(x) + x/f(x)=0 where y(0)=y'(1)=0 and x is in the range of (0,1) so far I have > de := diff(y(x),x,x)+x/y(x)=0; > ics := y(0)=0, D(y)(1)=0; > dsolve({de,ics}); / 2 \ | d | x de := |---- y(x)| + ---- = 0 | 2 | y(x) \ dx / ics := y(0) = 0, D(y)(1) = 0 it is not solving. Is there anything I' doing wrong?