Easy way to solve 3 equation simultaneously?:

Download Q_solve.mw

Determine all pairs of positive integers (x;y) such that: sqrt(x) + sqrt(y) = sqrt(637)

I would like to keep writing commands on the same line without automatically creating a new line break. Is there a way to achieve this in Maple?

In here i replaced but i don't know why still the D[1](f)(x, y, 0, t) is remain in my function in equation eqt1, beside this my function contain imaginary part we can plot this or we have to remove that somehow?

eval.mw

How to solve this equation to get the the similar plots given in pdf peristatic_flow_work.pdf

here is the work sheet for the problem which is given in the pdf 

Download pulatile_flow_error.mw

I want to change the datatype of a column of a Dataframe imported from Excel.

The import succeeds, and I can change the data type of numeric columns (from the default 'anything' to, say, float).

But conversion fails for all string columns. For example:

DataNew := SubsDatatype(Data, "UN Region", string);

throws the following error:

Error, (in DataSeries:-SubsDatatype) in datatype conversion; try using the 'conversion' option for data type string

The column in question has values such as "Southern Asia", which I would have thought would convert.

What am I doing wrong?

Groupings([a, b, ..., n], k)

Is there a built-in function in Maple that generates all possible groupings of the elements [a, b, ..., n] taken k at a time?

Example:

Groupings([a,b,c,d], 2)

Expected output:

[[[[a, b], c], d], [a, [[b, c], d]], [[a, [b, c]], d], [a, [b, [c, d]]], [[a, b], [c, d]]]

B12 := -6*(p1 + p2)/(p1 - p2)^2;
F2 := (theta1*theta2*p1^2 + (-2*p2*theta1*theta2 - 6)*p1 + theta1*theta2*p2^2 - 6*p2)/(p1 - p2)^2;

to..

F2 := theta1*theta2 + (-6*p1 - 6*p2)/(p1 - p2)^2
F2:= theta1*theta2 + B12  ( how to get this ?)

Should be very easy, but it is not 

For the NonlinearFit function in the Statistics package, how can I determine initial values that will allow it to solve and not diverge in this case: NonlinearFit((p1*x^2 + p2*x + p3)/(q1*x + x^2 + q2), Ycg, Sx, x) returns with:

"Warning, limiting number of iterations reached" and displays the coefficient values when it gave up. Clearly they were diverging and it was never going to find a solution. Here are values it stopped with:

[p1=583621.008503822, p2 = 59223.7407763244, p3 = 92888.8332296935, q1 =6192.35371505405, q2 = 230.127618843129]

If I give it good guesses, it finds the solution:

iv := [p1 = 494.8, p2 = -156, p3 = 12.45, q1 = -0.2884, q2 = 0.02548];
NonlinearFit((p1*x^2 + p2*x + p3)/(q1*x + x^2 + q2), Ycg, Sx, x, initialvalues = iv);

[p1=494.772354721411,p2=-155.993031307792, p3 = 12.4504112058999, q1 = -0.288444965762112, q2 = 0.0254838840984013]

The problem is, I got the initial values from the MATLAB Curve Fitting Toolbox. I would like be to use Maple alone and not need MATLAB for cure fitting. How can I compute initial values that will allow Maple to find a solution?

Did you intend on doing the diffetentiation elememtwise, ie. on each of the Matrix entriez?

Did you try,

   diff~(V, x)

or,

  map(diff, V, x)

?

I defined a 2×2 matrix V with entries involving operator-valued fields u(x,t), ω(x,t), and scalar function β(t). On macOS with Maple 2024.0, when I try to compute the derivative with respect to x using 

Vx := (diff, V, x);

Maple does not return a result. It just shows “Evaluating”

Download derivativve.mw

I created an image by a matrix 8x8:

M:=1/255*RandomMatrix(8,generator=0..255):
G:=convert(M,image):
Embed(G)

but the image dispayed is very small, of course. Is there a way to visualize the 8x8 pixel image larger, so I can see the pixels?

While solving for i1 encounter too many terms. How can I simplify it so that only " Pn,Pr and w" remain, with all other variables grouped into constants, so that the equation for the optimal i1​ becomes small and manageable?

Download Q_Simplify.mw

any idea what match fail on this example? is somethinbg wrong I am doing?

Download why_match_fail_sept_21_2025.mw

Update:
I think match can only do it if the main "variable"   is a variable and not a "function". In this example y(.) is function, so that is why it failed to match. For example this works:

A:=2*y^3+4;
match(A=k1*y^k2+k3,y,'la')

And gives true, since "y" here is not a "function".

But this makes match not very useful to use for parsing. patmatch seems a little more practical to use.

in this method i don't know in most of short equation i try to find the parameter but is just evaluating and nothing come up i don't know my way is wrong or write but i think i am right  but parameter not coming out, beside this in this equation give  me a warning regarding the parameters which say number of solution is more than 100 and dint show me that , how i can find the solution better than this?

f-p-.mw