dune03

12 Reputation

2 Badges

18 years, 36 days

MaplePrimes Activity


These are replies submitted by dune03

Daer Axel Vogt Starting from an equation,I calculate its differentiate with respect to x2. The differentiate gives me: difprofit22 := -1/54*L^2-1/9*(-x[1]^2-3*x[1]+3*x[2]+x[2]^2+1)*(3+2*x[2])/(-x[1]+x[2])+1/18*(-x[1]^2-3*x[1]+3*x[2]+x[2]^2+1)^2/(-x[1]+x[2])^2 . Now, I try to find the solutions of this differentiate with respect to x2. When I solve the result for x2 (solve (difprofit22,x2)), I find a polynomial function of degree 4 , like: RootOf(9*_Z^4+(36-12*x[1])*_Z^3+(33+L^2-6*x[1]^2-72*x[1])*_Z^2+(-66*x[1]+36*x[1]^2+12*x[1]^3-2*L^2*x[1])*_Z-3+L^2*x[1]^2-3*x[1]^4+33*x[1]^2) Is there a mean to express the roots of this polynom in a simplier way with x1 and L, knowing that I'm working in real domain with Z between ]-3/2,3/2], x[1]>Z, x[1] between [-3/2,3/2[, and 0. I need to obtain this solution to integrate it in an another differentiate for find a solution with respect to x1, this time. Thanks
Daer Axel Vogt Starting from an equation,I calculate its differentiate with respect to x2. The differentiate gives me: difprofit22 := -1/54*L^2-1/9*(-x[1]^2-3*x[1]+3*x[2]+x[2]^2+1)*(3+2*x[2])/(-x[1]+x[2])+1/18*(-x[1]^2-3*x[1]+3*x[2]+x[2]^2+1)^2/(-x[1]+x[2])^2 . Now, I try to find the solutions of this differentiate with respect to x2. When I solve the result for x2 (solve (difprofit22,x2)), I find a polynomial function of degree 4 , like: RootOf(9*_Z^4+(36-12*x[1])*_Z^3+(33+L^2-6*x[1]^2-72*x[1])*_Z^2+(-66*x[1]+36*x[1]^2+12*x[1]^3-2*L^2*x[1])*_Z-3+L^2*x[1]^2-3*x[1]^4+33*x[1]^2) Is there a mean to express the roots of this polynom in a simplier way with x1 and L, knowing that I'm working in real domain with Z between ]-3/2,3/2], x[1]>Z, x[1] between [-3/2,3/2[, and 0. I need to obtain this solution to integrate it in an another differentiate for find a solution with respect to x1, this time. Thanks
Dear Axel Vogt, Thanks for you reply, but this give me a numerical solution or I'm looking for an analytical one, like Z=f(x1,L). The domain of x1, L and Z are small, so is there a way to integrate this in the routine and so reduce the domain of solutions for "solve"? Thanks for you help!
Dear Axel Vogt, Thanks for you reply, but this give me a numerical solution or I'm looking for an analytical one, like Z=f(x1,L). The domain of x1, L and Z are small, so is there a way to integrate this in the routine and so reduce the domain of solutions for "solve"? Thanks for you help!
Page 1 of 1