kail85

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9 years, 12 days

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These are replies submitted by kail85

solve identity is working for this simple case, but actually my question is simplified from:

f:= a exp(x) + b exp(2*x) = 2 exp(x) + 5 exp(2*x)

I have tried match, but match cannot accept exp(x) as variabe. Instead of subs exp(x) as a single variable, is there any other better method? 

 

Many thanks

Kyle

solve identity is working for this simple case, but actually my question is simplified from:

f:= a exp(x) + b exp(2*x) = 2 exp(x) + 5 exp(2*x)

I have tried match, but match cannot accept exp(x) as variabe. Instead of subs exp(x) as a single variable, is there any other better method? 

 

Many thanks

Kyle

The pic for the equation is not shown.

the equation is:

a x + b y = 2 x + 5 y

 

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