mapleatha

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5 years, 329 days

MaplePrimes Activity


These are replies submitted by mapleatha

@Kitonum 

Kitonum, I cannot use your second suggestion because evrything happens programmatically.

Q below is a copy of the Maple output with the parentheses around the integral.

Q:=-(Int(x^2,x));

op(1,Q) = -1

op12:=op(1,op(2,Q)) = x^2

parout:=algsubs(-(Int(op12,x))=-RTABLE(1,%int(op12,x)),Q);

The parentheses are gone. We are done.

I have used RTABLE extensively in Maple 13. I don't think it works properly in Mape 2018, etc.
Thank you very much.

mapleatha

 

 

 

 

@Kitonum 

Thank you, @Kitonum, but this doesn't work in Maple 13.

mapleatha

@Kitonum 

 

Thank you!

@tomleslie 

Thank you!

@Carl Love 

Thank you!

@Carl Love 

Thank you, Carl Love. I did define _F1 to be the identity function,
but it didn't work beautifully like your definition.

mapleatha

@Preben Alsholm 

 

Thank you, Preben!

@Joe Riel 

What does " modify the character styles appropriately" mean? It means nothing to me. Which style is it talking about? All I get is a listing of fonts. I enter a word and change its font to my liking. What did I just do? Which font in my display of maple programming have I changed? What does "Export your style set" mean? How come there is no example on the planet Earth that shows you how to do these things?
Thank you very much for your respone. Naturally, I had read all that a million times.

mapleatha

 

@acer 

acer,

Thank you so much for your help. Luckily, in the type of the inverse Laplace
transforms that I am considering, the solution always contains "RootOf" for the complex roots.
So, I convert the solutions to strings and look for "RootOf" in them. When I find one
occurrence, I avoid printing the respective solution.
Thank you again!

mapleatha

@acer 

Yes, acer. I just discovered that. I used sol:=solve([eq1,...,eq6],[a,b,c,d,f,g]); This is how I got the list that I can handle.
Thank you!
Would you also be kind enough to tell me how to get only real solutions?
Thank you again!

mapleatha

I think I have an answer to the first question. I can get the result of "solve" as a list, and then I can get the number of
elements of the list of solutions, or the (i,j)-th element of each solution list.
Thank you.

mapleatha

@acer 

That is not case, @acer.

The terms that are  missing are not there anymore. They leave no trace.
It is OK, though. I can solve the problem by using lists.
Sorry for bothering you.
Thank you!

mapleatha
 

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