Maple 2019 Questions and Posts

These are Posts and Questions associated with the product, Maple 2019


Without any success, I've been trying to hide the input/code, such that only the output (moment and shear) diagram is shown. I've tried guides with Document Blocks method but all seem outdated, since they're referring to commands which don't seem to exist i.e. "collapse document block". I can't understand that there isn't some neat and user-friendly way to something as simple as show/hide the input, to make it more document-reader friendly? It seems the only way is to just hightlight the input and color it white, which isn't too viable long term. 

I hope you can help, it would be alot of help to me and my classmates. 
Kind regards and thanks for your time.


PS. Here's a picture of the input and diagram.


Every once-in-a-while Maple crashes due to a bug in numerical integration that I reported ages ago, but was never fixed (or if it was, I was never told). Anyway, this time, in addition to crashing, it wiped out my worksheet, and froze the machine. When I recovered, Maple had lost all memory of my preferences, recent files, etc - it was as if I had a clean installation.

I restored the link to the usual style file I use, but it still refuses to give me back the style I want - that is - the classical worksheet. Every command I enter now requires F5 or I will get 2D input which I hate. Does anyone know where the preferences, probably an .INI file, are kept, so I can restore it from an older version of Maple.

Thank you

Hi, i am using solve and solve command to find the root but when i used fsolve command to separate only real root, could separate all roots, can anyone correct me, please



f := 9.765625000*10^(-6)*(-6671.221362*(x^2+2)^5*sqrt(2)*arctan((1/2)*x*sqrt(2))*x-555.9351135*(x^2+2)^6/((1/2)*x^2+1)-10479.13001*(x^2+2)^5*sqrt(2)*x-(374220*(0.297116730e-1*x^9+.269385824*x^7+.99643086*x^5+5.18951288*x^3+4.42867382*x))*x-1111.870227*x^10-12601.19538*x^8-62147.39274*x^6-485504.8775*x^4-828649.1585*x^2-788850.2769)/(x^2+2)^6-(0.1171875000e-3*(-555.9351135*(x^2+2)^6*sqrt(2)*arctan((1/2)*x*sqrt(2))-873.2608343*(x^2+2)^6*sqrt(2)-(374220*(0.29711673e-2*x^10+0.33673228e-1*x^8+.16607181*x^6+1.29737822*x^4+2.21433691*x^2+2.107985348))*x))*x/(x^2+2)^7+(3.484800000*sqrt(2)*(x^2+2)*arctan((1/2)*x*sqrt(2))*x+.8712000000*(x^2+2)^2/((1/2)*x^2+1)+(5.473911040*(x^2+2))*sqrt(2)*x+5.227200000*x^2-22.99200001)/(16*(x^2+2)^2)-(.8712000000*sqrt(2)*(x^2+2)^2*arctan((1/2)*x*sqrt(2))+1.368477760*sqrt(2)*(x^2+2)^2-36*x*(-0.484000000e-1*x^2+.638666667))*x/(4*(x^2+2)^3)



ip := solve(f = 0, x)

.6540411301, 3126.002498+5414.398621*I, .4137989369+1.038962897*I, .6364817315+1.870977651*I, -.6364817315+1.870977651*I, -.4137989369+1.038962897*I, -.6540411301, -6252.010299, -.4137989369-1.038962897*I, -.6364817315-1.870977651*I, .6364817315-1.870977651*I, .4137989369-1.038962897*I, 3126.002498-5414.398621*I


cp := fsolve(numer(f) = 0, x)






Hello! I would like to ask a short question about particularsol function. Could someone please explain to me, why the function interprets the cosinus term as particular solution, even though it is homogeneous solution? Is it a bug in Maple or I unterstand something wrong?

As the title states, I want to have an equation f(x), and f(x) = 0 if x < 0, f(x) = x if x >= 0. How could I accomplish this?

I'm actually trying to generating a differential equation something like y'(x) + k*h(y) = sin(x) where h(y) is what I described above. Is there any convenient way to do this?


I'm new to Maple and was wondering if anyone could help me with how to put a discrete distribution such as Pr(X=1)=0.25, Pr(X=2)=0.65, Pr(X=3)=0.1, into Maple.


Dear community, please help me to verify that the obtained solution by using the fsolve command of maple is correct or wrong? and one more question how to generate interval in which our solution should be contained. dear admin if my question is duplicate please do not delete. please have a look on my maple file

To solve this, I got this far but am not sure where to go next?


f2 := x^2 - 3;
f2d := diff(f2, x);
                             x  - 3
                              2 x

set value for x0, number precision

x0 := 3;
eps := 0.1*10^(-5);


in the ThermophysicalData[Chemicals] package that compute the coefficients for different species how I can find that coefficients for seven coefficients not nine of them

in other words, I am seeking to find Databases for the NASA Seven-Coefficient Polynomial Fits for Calculating Thermodynamic Properties of Individual Species.



My equations are not getting solved.

Please tell me, is there any other command to solve these type of equations.



I have an issue where I believe the values given by evalf (I have independent verification), but the plot of the same function is incorrect. Specifically, g(a) plotted for a <=0 is correct, and incorrect for a > 0.

What am I doing wrong?

plot(g(a), a=-2..5) #I don't believe anything for a > 0

evalf(g(-1)) #I believe all of these values













The Fitting Procedure

The data are T,CP,H and S. I need to determine a polynomial with seven Coefficients.

The essential input to the fitting procedure is a table of specific heat, enthalpy, and entropy as a function of temperature. 

The constrained linear least-squares fitting procedure is a three-stage process. The first step is to determine simultaneously a1, through a5 for temperature ranges by fitting the specific heats to Eq. (1).

 The second step is to determine a6 for temperature ranges by fitting the H data. In this state, a1-a5 are held fixed, and as in the cp fitting, equality constraints on the fit and its first derivative are imposed at the common temperature. Finally, the a7 coefficients are determined by fitting the entropy (S) data.



Maple Worksheet - Error

Failed to load the worksheet /maplenet/convert/ .


Hello experts,I need your help to obtain the solution of the mentioned equation in the attached picture by using the newton method by supposing the random value of involved constant like D  etc. I need an algorithm for the newton method for the mentioned equation. note h=1+x^2/2

Hello everyone, I want to the expression for Q after putting T=0, pls help me to solve it.pls have the attachment



(1/12)*6^(1/2)*((n-1)*(-15*k^2*n+15*k^2-30*k*n+30*k-15*n+15+(1920*n*q*sigma^6-1920*q*sigma^6+225*k^4*n^2+5760*Q*n*sigma^3-450*k^4*n+900*k^3*n^2-5760*Q*sigma^3+225*k^4-1800*k^3*n+1350*k^2*n^2+900*k^3-2700*k^2*n+900*k*n^2+1350*k^2-1800*k*n+225*n^2+900*k-450*n+225)^(1/2)))^(1/2)/(sigma^2*(n-1)), -(1/12)*6^(1/2)*((n-1)*(-15*k^2*n+15*k^2-30*k*n+30*k-15*n+15+(1920*n*q*sigma^6-1920*q*sigma^6+225*k^4*n^2+5760*Q*n*sigma^3-450*k^4*n+900*k^3*n^2-5760*Q*sigma^3+225*k^4-1800*k^3*n+1350*k^2*n^2+900*k^3-2700*k^2*n+900*k*n^2+1350*k^2-1800*k*n+225*n^2+900*k-450*n+225)^(1/2)))^(1/2)/(sigma^2*(n-1)), (1/12)*(-6*(n-1)*(15*k^2*n-15*k^2+30*k*n+(1920*n*q*sigma^6-1920*q*sigma^6+225*k^4*n^2+5760*Q*n*sigma^3-450*k^4*n+900*k^3*n^2-5760*Q*sigma^3+225*k^4-1800*k^3*n+1350*k^2*n^2+900*k^3-2700*k^2*n+900*k*n^2+1350*k^2-1800*k*n+225*n^2+900*k-450*n+225)^(1/2)-30*k+15*n-15))^(1/2)/(sigma^2*(n-1)), -(1/12)*(-6*(n-1)*(15*k^2*n-15*k^2+30*k*n+(1920*n*q*sigma^6-1920*q*sigma^6+225*k^4*n^2+5760*Q*n*sigma^3-450*k^4*n+900*k^3*n^2-5760*Q*sigma^3+225*k^4-1800*k^3*n+1350*k^2*n^2+900*k^3-2700*k^2*n+900*k*n^2+1350*k^2-1800*k*n+225*n^2+900*k-450*n+225)^(1/2)-30*k+15*n-15))^(1/2)/(sigma^2*(n-1))





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