Shift+Left Arrow to choose the region which I'll make them numerator part,or add parentheses for the part.

 

(6+7)/

Any other convenient methods?

how to approach this problem: for what value of a, the expression is minimum:- g(n,a):=(1+1/(n))^(((n^(1/(a))+(n+1)^(1/(a) ))/(2))^(a))-exp(1) the answer seems to a=3.

F₂:

 + | 0 1        × | 0 1
 --+----        --+----
 0 | 0 1        0 | 0 0
 1 | 1 0        1 | 0 1

F₃:

 + | 0 1 2       × | 0 1 2
 --+------       --+------
 0 | 0 1 2       0 | 0 0 0
 1 | 1 2 0       1 | 0 1 2
 2 | 2 0 1       2 | 0 2 1

F₄:

Actually I reach that in mathematica not easy,

Show[Plot[
  Piecewise[{{0, x < -0.5}, {1/5, x < 1.3}, {2/5, x < 1.7}, {3/5,
     x < 2}, {4/5, x < 2.8}, {1, x > 2.8}}], {x, -2, 5},
  Ticks -> {{-0.5, 1.3, 1.7, 2, 2.8}, {1/5, 2/5, 3/5, 4/5, 1}},
  PlotStyle -> {Thickness[0.01]}],
 ListPlot[{{-0.5, 1/5}, {1.3, 2/5}, {1.7, 3/5}, {2, 4/5}, {2.8, 1}},
  PlotStyle -> PointSize[0.03]]]

is this identity true (i believe it is)?

 

p*int(f,x=0..infinity) = sum ((int(f,x=n..n+p)),n=0..n+p) + sum((p-n)*(int(f,x=n-1..n)),n=1...p-1)

 

p*(int(f(x), x = 0 .. infinity)) = sum(int(f(x), x = n .. n+p), n = 0 .. n+p)+sum((p-n)*(int(f(x), x = n-1 .. n)), n = 1 .. p-1)

 

If it is true how we understand it, and understand it through Maple.

I have a set of data. The number of times an event occurred each day. So my data set looks like, [[daynum, numevents]] == [[1,3],[2,1],[3,5],...] where daynum is the day number, and numevents is the number of times an event occurred that day. What I want to do is plot these like a histogram, or barchart, or column graph (I'm not very good at stats, so I may not know what I'm talking about here) - anyway, something like that - with daynum on the horizontal axis and numevents on the vertical axis. And the numevent should be a tall rectangle with height = numevent value.

My first question is :   How can I count the number of recent calls to a procedure (not exprofile) ?

for example:

X := proc ()
Sample(RandomVariable(Normal(0, 1)), 1)[1]
end proc;
X();  X() ;

should return 2
 

 

My second question is:  

I have a procedure as seen below which I plot in a component plot  Do(%Plot0=X(%Slider_mu,%Slider_sigma,%Slider_t));

The Do call has 3 sliders inputs in the form of mu, sigma, tt.

ComplexExpand[(1 + I)^n + (1 - I)^n]

this is in mathematica

 

In the previous post, I described why parallel programming is hard. Now I am going to start describing techniques for writing parallel code that works correctly.

First some definitions.

• thread safe: code that works correctly even when called in parallel.
• critical section: an area of code that will not work correctly if run in parallel.
• shared: a resource that can be accessed by more than one thread.
• mutex: a programming tool that controls access to a section of code

I am taking a LA course, no problem with the math.  But Maple I don't know, and we are using Maple 12 student edition.  I have never used Maple and our underly-helpful teacher's answer is "go watch the training videos".

Here

I am taking a LA course, no problem with the math.  But Maple I don't know, and we are using Maple 12 student edition.  I have never used Maple and our underly-helpful teacher's answer is "go watch the training videos".

Here

how to convert the vertical output to horizontal,and how to cite the result.

 

 for n to 20 do evalf(f(n)) end do;

I know very little about the Kalman filter. The thing that I do know is that the Kalman filter has great potential.

However I am not sure that I want to invest time doing reasearch on it because I am not sure I

will be able to come up with an working model in Maple. Does anyone have any experience with Kalman filter in Maple ?

Does anyone want to explain how such a model works ?!

HI there, I have a quick question and I just want to confirm what I found. I was trying to do some Fourier Transform using the MTM package and I was successful in doing so for one dimensional problems when it's only f(x) but when I tried to do something more complicate like 2D fourier transform when the f is a function of x and y ie. f(x,y), Maple seems not able to do it. I checked with help menu and it seems it can support only 1D. is there anything other package that I'm not aware of that is capable of a such thing?

Greetings All

I just wanted to test some values in the Rydberg Formula:

eq1 := 1/L = R(1/nfinal^2-1/nstart^2)

sol1:= solve(eq1, L)

and the answer looks correct:

1/R(-(-nstart^2+nfinal^2)/(nfinal^2*nstart^2))

 

But when I go and try and solve for these other variables I get

solve(eq1, nfinal)  ----->  I get an "Error, (in evala/Reduce/ff/monomial) numeric exception: division by zero"

solve(eq1, nstart)  --->   I get nfinal^2/(-1+RootOf(R(_Z)*L-1)*nfinal^2)