Maple Questions and Posts

These are Posts and Questions associated with the product, Maple

MAPLE 15 on Windows 10

I have a file on which I can no longer open. This happened after my computer made me long on again after being gone for a little while. Maple was not running when I got back on. This is not unusal and I just clinck on the file and restart.

This time this did not work.

It comes up with a message asking me to select an input mode. Whatever I select even 'Plain text' it just hangs.

I'd send you an image, but I don't see how to do it. The button provide only allows for something with  url and the snip I made is on my desktop.

I need to get thiis worksheet back. I've put a lot of effort into it.

-Traruh

Here is my code in Maple.

 

#Solve the initial-value problem using the technique of question 2. Find the implicit solution.
eqn3:=(exp(x)+y)*dx+(2+x+y*exp(y))*dy=0;
(exp(x) + y) dx + (2 + x + y exp(y)) dy = 0
#subject to y(0)=1.
M:=exp(x)+y; N:=2+x+y*exp(y);
exp(x) + y
2 + x + y exp(y)
int(M, x); int(N,y);
exp(x) + y x
y x + 2 y + y exp(y) - exp(y)
implicitsoln1 := exp(x)+y*x+2*y+y*exp(y)-exp(y)=C;
exp(x) + y x + 2 y + y exp(y) - exp(y) = C
y1 := solve(implicitsoln1,y);
RootOf(-exp(_Z) _Z - _Z x + C + exp(_Z) - 2 _Z - exp(x))
C:=subs({x=0,y=1},lhs(implicitsoln1));
exp(0) + 2
y1;

 

How do I get it to to not have "root of" and give me a more specific solution.

After running Maple in a shell file, I come up with this error that I do not understand on my Mac,

gap_long := 0.117647058823529 Pi

gap_lat := 0.0588235294117647 Pi

lat_begin := 0.441176470588235 Pi

long_begin := -Pi

lat_begin_0 := 0.441176470588235 Pi

long_begin_0 := -Pi

long_max := 0.882352941176471 Pi

lat_max := -0.441176470588235 Pi

33

Warning, `parameter` is implicitly declared local to procedure `set_par_eff`

distance eff distance_eff
im in has not
im in has not
im in has not
im in has not
im in has not
im in has not
im in has not
im in has not
im in has not
Im in has par
Im in has par
Error, invalid input: eval expects its 2nd argument, eqns, to be of type
{integer, equation, set(equation)}, but received par_eff_post
13

32

31

17

hou := 0

mini := 0

seci := 0

memory used=4.0MB, alloc=32.3MB, time=0.23



If needed, I can attach more files if my question is still a bit too cryptic. Please let me know asap as this is urgent. Thank you so much,
-Z

 

 

Hi all,

 

Please help me with this question. I want to solve a PDE by Maple.

restart

A := 5;

5

(1)

B := 9

9

(2)

c := 1

1

(3)

``

``

``

eq := diff(u(x, t), t, t)-c^2*(diff(u(x, t), x, x));

diff(diff(u(x, t), t), t)-(diff(diff(u(x, t), x), x))

(4)

 

dsolve({eq, u(0, t) = A, u(1, t) = B, u(x, 0) = 0, (D(u))(x, 0) = sin(x)}, u(x, t))

Error, (in evalapply/D) too many variables for the derivative of a function of only one variable in D(u)(x, 0)

 

``

``

``

 

Download SolvePDE.mwSolvePDE.mw

Dear All

Say I have created a Maple module called MYMODULE. This means that I have a .mpl file called

mymodule.mpl, with inside

   MYMODULE := module()

   export myfunction;

   ****

   ****

   end module:

   savelib(MYMODULE, "MYMODULE.mla"):

Hence I use it in such a way:

> with(MYMODULE);

                                                              [myfunction]

I want to associate a help to the function myfunction. I know that with Maple18 things have changed

but I am not able to find enough information online. Say I have a .txt file called help_myfunction.txt.

How can I enable this help for my function, so that at the command

> ?myfunction;

the content of help_myfunction.txt shows up?

 

Many thanks,Simone

 

I have two sets 

f:={1,2,3,4};

h:={1,2,4,5}

L=seq(i,i=1..4):

I want to program , if it is true that f[i] = h[i], then it prints f[i]. So the output should be {1,2}.

for i in L do
if evalb(f[i]=h[i]) then
print(f[i]);
end if;
end do;

I get no output. https://i.imgur.com/qA5hU3i.png

I tried changing the set f to list, f:= [1,2,3,4], still no output.

Hi...

 

I want to solve  this ODEs using Maple...

f’’’ + f f’’ – f’2 + λ θ = 0

(1/Pr) θ’’ + f θ’ – f’ θ = 0


and boundary conditions

f(0) = s,  f’(0) = σ + a f’’(0) + b f’’’(0),  θ(0) = 1,

f’(η) = 0, θ(η) = 0  as  η → ∞.

 

Can anyone help me to solve this problem? Thank you... =)

hi 

how i can apply this differential in maple?

thabks...

 

hi .please help me for solve this equations.

bbb2.mw

restart; d[11] := 1; mu[11] := 1; q[311] := 1; d[33] := 1; mu[33] := 1; a[11] := 1; e[311] := 1; a[33] := 1; A := 1; g[111111] := 1; c[1111] := 1; g[113113] := 1; f[3113] := 1; beta[11] := 1; `ΔT` := 1; II := 1; L := 1

J := d[11]*(diff(Phi(x, z), x, x))+mu[11]*(diff(psi(x, z), x, x))+q[311]*(diff(w(x), x, x))+d[33]*(diff(Phi(x, z), z, z))+mu[33]*(diff(psi(x, z), z, z));

diff(diff(Phi(x, z), x), x)+diff(diff(psi(x, z), x), x)+diff(diff(w(x), x), x)+diff(diff(Phi(x, z), z), z)+diff(diff(psi(x, z), z), z)

(1)

B := a[11]*(diff(Phi(x, z), x, x))+d[11]*(diff(psi(x, z), x, x))+e[311]*(diff(w(x), x, x))+a[33]*(diff(Phi(x, z), z, z))+d[33]*(diff(psi(x, z), z, z));

diff(diff(Phi(x, z), x), x)+diff(diff(psi(x, z), x), x)+diff(diff(w(x), x), x)+diff(diff(Phi(x, z), z), z)+diff(diff(psi(x, z), z), z)

(2)

R := A*(g[111111]*(diff(u[0](x), x, x, x, x))-c[1111]*(diff(u[0](x), x, x)+(1/2)*(diff((diff(w(x), x))^2, x)))+e[311]*(diff(diff(Phi(x, z), z), x))+q[311]*(diff(diff(psi(x, z), z), x)));

diff(diff(diff(diff(u[0](x), x), x), x), x)-(diff(diff(u[0](x), x), x))-(diff(w(x), x))*(diff(diff(w(x), x), x))+diff(diff(Phi(x, z), x), z)+diff(diff(psi(x, z), x), z)

(3)

S := -II*g[111111]*(diff(w(x), x, x, x, x, x, x))-II*c[1111]*(diff(w(x), x, x, x, x))+A*g[113113]*(diff(w(x), x, x, x, x))-A*f[3113]*(diff(diff(Phi(x, z), z), x, x))-A*(c[1111]*(diff(u[0](x), x, x)+(1/2)*(diff((diff(w(x), x))^2, x)))+e[311]*(diff(diff(Phi(x, z), z), x))+q[311]*(diff(diff(psi(x, z), z), x)))*(diff(w(x), x))-A*(diff(w(x), x, x))*(c[1111]*(diff(u[0](x), x)+(1/2)*(diff(w(x), x))^2)+e[311]*(diff(Phi(x, z), z))+q[311]*(diff(psi(x, z), z))-beta[11]*`ΔT`);

-(diff(diff(diff(diff(diff(diff(w(x), x), x), x), x), x), x))-(diff(diff(diff(Phi(x, z), x), x), z))-(diff(diff(u[0](x), x), x)+(diff(w(x), x))*(diff(diff(w(x), x), x))+diff(diff(Phi(x, z), x), z)+diff(diff(psi(x, z), x), z))*(diff(w(x), x))-(diff(diff(w(x), x), x))*(diff(u[0](x), x)+(1/2)*(diff(w(x), x))^2+diff(Phi(x, z), z)+diff(psi(x, z), z)-1)

(4)

dsys := {B, J, R, S}; BCS := {D@@2*w(0) = 0, D@@2*w(L) = 0, Phi(x = 0) = 0, Phi(x = L) = 0, Phi(z = -(1/2)*h) = 0, Phi(z = (1/2)*h) = 0, psi(x = 0) = 0, psi(x = L) = 0, psi(z = -(1/2)*h) = 0, psi(z = (1/2)*h) = 0, w(x = 0) = 0, w(x = L) = 0, u[0](x = 0) = 0, u[0](x = L) = 0, (D(w))(0) = 0, (D(w))(L) = 0, (D(u[0]))(0) = 0, (D(u[0]))(L) = 0}

{D@@2*w(0) = 0, D@@2*w(L) = 0, Phi(x = 0) = 0, Phi(x = L) = 0, Phi(z = -(1/2)*h) = 0, Phi(z = (1/2)*h) = 0, psi(x = 0) = 0, psi(x = L) = 0, psi(z = -(1/2)*h) = 0, psi(z = (1/2)*h) = 0, w(x = 0) = 0, w(x = L) = 0, u[0](x = 0) = 0, u[0](x = L) = 0, (D(w))(0) = 0, (D(w))(L) = 0, (D(u[0]))(0) = 0, (D(u[0]))(L) = 0}

(5)

dsol5 := dsolve(dsys, numeric)

Error, (in dsolve/numeric/process_input) missing differential equations and initial or boundary conditions in the first argument: dsys

 

NULL

NULL

NULL

if former equations are not solvable , please help me for another way, in which at first two equation solve..in this way in equation [J and B] assume that q[311]=e[311]=0 and dsolve perform to find Φ and  ψ

after by finding Φ and  ψ is use for detemine w and u0

please see attached file below[bbb2_2.mw]

bbb2_2.mw

Download bbb2.mw

I have the following PDE system steaming from Flash Photolysis:

pdesys := [diff(J(x, t), x) = varepsilon*J(x, t)*C(x, t), diff(C(x, t), t) = phi*varepsilon*J(x, t)*C(x, t)]

when I use pdsolve(pdesys,[J,C]) I get:

{C(x, t) = 0, J(x, t) = _F1(t)}, {C(x, t) = _F1(x)*_C1, J(x, t) = 0}

The solution appears to be either C(x,t) = 0 or J(x,t) = 0. This are the obvious solutions (0 = 0). I have the analytical solution to this PDE system where neither C(x,t) nor J(x,t) are 0.

How to solve this system in maple? Thanks.

 

Hi

In attached mw file I have a equation that "a" is in unknown parameter. X and Y are matrixes of data. How can I calculate the "a" parameter?

Best regard

question.mw

Example 6 from Maple Help.

 

restart:

with(Optimization):

LPSolve(2*x+5*y, {3*x-y = 1, x-y <= 5}, assume = {integer, nonnegative})

 

Kernel crash the same with Maple 2015.

 

Does anyone can confirm?

Mariusz Iwaniuk

hi.please help me for solve this equation

i encounter with error''

Error, (in StringTools:-IsPrefix) second argument must be a string''

equations which be solved attached as pdf file

thanks

Kernel4.mw

root.pdf


 

restart

with(LinearAlgebra):

Typesetting:-Settings(functionassign=false):

NULL

Constants

 

landa := 0.404e11; -1; mu := 0.27e11; -1; alpha := 0.23e-4; -1; rho := 2707; -1; k := 204; -1; c := 903; -1; nu := .3; -1; E := 0.70e11; -1; T0 := 293; -1; omega := 0.1e-1

0.1e-1

(1.1.1)

beta := alpha*(3*landa+2*mu):

NULL

varpi := 0.1e-1; -1; No := 15

15

(1.1.2)

 

 

Eq[1] := besselj(0, xi*b)*(eval(diff(bessely(0, xi*r), r), r = a))-(eval(diff(besselj(0, xi*r), r), r = a))*bessely(0, xi*b):

 

wf1 := unapply(Eq[1], xi):

1

 

1.794010904

 

1

 

2

 

1.794010904

 

1

 

3

 

4.802060761

 

2

 

4

 

4.802060761

 

2

 

5

 

4.802060761

 

2

 

6

 

7.908961712

 

3

 

7

 

7.908961712

 

3

 

8

 

7.908961712

 

3

 

9

 

11.03509457

 

4

 

10

 

11.03509457

 

4

 

11

 

11.03509457

 

4

 

12

 

11.03509457

 

4

 

13

 

14.16798650

 

5

 

14

 

14.16798650

 

5

 

15

 

14.16798650

 

5

 

16

 

17.30400975

 

6

(1.2.1)

Eq[2] := MTM:-besselj(1, eta*b)*(eval(diff(MTM:-bessely(1, eta*r), r), r = a))-(eval(diff(MTM:-besselj(1, eta*r), r), r = a))*MTM:-bessely(1, eta*b):

wf2 := unapply(Eq[2], eta):

1

 

1.958510605

 

1

 

2

 

1.958510605

 

1

 

3

 

4.857021628

 

2

 

4

 

4.857021628

 

2

 

5

 

4.857021628

 

2

 

6

 

7.941288451

 

3

 

7

 

7.941288451

 

3

 

8

 

7.941288451

 

3

 

9

 

11.05802155

 

4

 

10

 

11.05802155

 

4

 

11

 

11.05802155

 

4

 

12

 

11.05802155

 

4

 

13

 

14.18576207

 

5

 

14

 

14.18576207

 

5

 

15

 

14.18576207

 

5

 

16

 

17.31852918

 

6

(1.2.2)

 

for m to MM do K0[m] := proc (r, m) options operator, arrow; BesselJ(0, xi[m]*r)*BesselY(0, xi[m]*b)-BesselJ(0, xi[m]*b)*BesselY(0, xi[m]*r) end proc; KK0[m] := proc (r, m) options operator, arrow; diff(K0[m](r, m), r) end proc; K1[n] := proc (r, n) options operator, arrow; BesselJ(1, eta__n*r)*BesselY(1, eta__n*b)-BesselJ(1, eta__n*b)*BesselY(1, eta__n*r) end proc; KK1[n] := proc (r, n) options operator, arrow; diff(K1[n](r, n), r) end proc end do

proc (r, m) options operator, arrow; BesselJ(0, xi[m]*r)*BesselY(0, xi[m]*b)-BesselJ(0, xi[m]*b)*BesselY(0, xi[m]*r) end proc

 

proc (r, m) options operator, arrow; MTM:-diff(K0[m](r, m), r) end proc

 

proc (r, n) options operator, arrow; BesselJ(1, eta__n*r)*BesselY(1, eta__n*b)-BesselJ(1, eta__n*b)*BesselY(1, eta__n*r) end proc

 

proc (r, n) options operator, arrow; MTM:-diff(K1[n](r, n), r) end proc

 

proc (r, m) options operator, arrow; BesselJ(0, xi[m]*r)*BesselY(0, xi[m]*b)-BesselJ(0, xi[m]*b)*BesselY(0, xi[m]*r) end proc

 

proc (r, m) options operator, arrow; MTM:-diff(K0[m](r, m), r) end proc

 

proc (r, n) options operator, arrow; BesselJ(1, eta__n*r)*BesselY(1, eta__n*b)-BesselJ(1, eta__n*b)*BesselY(1, eta__n*r) end proc

 

proc (r, n) options operator, arrow; MTM:-diff(K1[n](r, n), r) end proc

 

proc (r, m) options operator, arrow; BesselJ(0, xi[m]*r)*BesselY(0, xi[m]*b)-BesselJ(0, xi[m]*b)*BesselY(0, xi[m]*r) end proc

 

proc (r, m) options operator, arrow; MTM:-diff(K0[m](r, m), r) end proc

 

proc (r, n) options operator, arrow; BesselJ(1, eta__n*r)*BesselY(1, eta__n*b)-BesselJ(1, eta__n*b)*BesselY(1, eta__n*r) end proc

 

proc (r, n) options operator, arrow; MTM:-diff(K1[n](r, n), r) end proc

 

proc (r, m) options operator, arrow; BesselJ(0, xi[m]*r)*BesselY(0, xi[m]*b)-BesselJ(0, xi[m]*b)*BesselY(0, xi[m]*r) end proc

 

proc (r, m) options operator, arrow; MTM:-diff(K0[m](r, m), r) end proc

 

proc (r, n) options operator, arrow; BesselJ(1, eta__n*r)*BesselY(1, eta__n*b)-BesselJ(1, eta__n*b)*BesselY(1, eta__n*r) end proc

 

proc (r, n) options operator, arrow; MTM:-diff(K1[n](r, n), r) end proc

 

proc (r, m) options operator, arrow; BesselJ(0, xi[m]*r)*BesselY(0, xi[m]*b)-BesselJ(0, xi[m]*b)*BesselY(0, xi[m]*r) end proc

 

proc (r, m) options operator, arrow; MTM:-diff(K0[m](r, m), r) end proc

 

proc (r, n) options operator, arrow; BesselJ(1, eta__n*r)*BesselY(1, eta__n*b)-BesselJ(1, eta__n*b)*BesselY(1, eta__n*r) end proc

 

proc (r, n) options operator, arrow; MTM:-diff(K1[n](r, n), r) end proc

 

proc (r, m) options operator, arrow; BesselJ(0, xi[m]*r)*BesselY(0, xi[m]*b)-BesselJ(0, xi[m]*b)*BesselY(0, xi[m]*r) end proc

 

proc (r, m) options operator, arrow; MTM:-diff(K0[m](r, m), r) end proc

 

proc (r, n) options operator, arrow; BesselJ(1, eta__n*r)*BesselY(1, eta__n*b)-BesselJ(1, eta__n*b)*BesselY(1, eta__n*r) end proc

 

proc (r, n) options operator, arrow; MTM:-diff(K1[n](r, n), r) end proc

(1.2.3)

U1 := -(int(r*K0[m]*(diff(K1[n], r)+K1[n]/r), r = a .. b))/(int(r*K0[m]^2, r = a .. b)); -1; U2 := -(int(r*K1[n]*(diff(K0[m], r)), r = a .. b))/(int(r*K1[n]^2, r = a .. b)); -1; U3 := (int(r^2*omega^2*K1[n], r = a .. b))/(int(r*K1[n]^2, r = a .. b))

0.1555555555e-3/K1[0]

(1.2.4)

m := 0; -1; for m to MM do M__m := int(r*K1[m](r, m)^2, r = a .. b); bb__m := 1/M__m end do

int(r*K1[1](r, 1)^2, r = 1 .. 2)

 

1/(int(r*K1[1](r, 1)^2, r = 1 .. 2))

 

int(r*K1[2](r, 2)^2, r = 1 .. 2)

 

1/(int(r*K1[2](r, 2)^2, r = 1 .. 2))

 

int(r*K1[3](r, 3)^2, r = 1 .. 2)

 

1/(int(r*K1[3](r, 3)^2, r = 1 .. 2))

 

int(r*K1[4](r, 4)^2, r = 1 .. 2)

 

1/(int(r*K1[4](r, 4)^2, r = 1 .. 2))

 

int(r*K1[5](r, 5)^2, r = 1 .. 2)

 

1/(int(r*K1[5](r, 5)^2, r = 1 .. 2))

 

int(r*K1[6](r, 6)^2, r = 1 .. 2)

 

1/(int(r*K1[6](r, 6)^2, r = 1 .. 2))

(1.2.5)

MM; 1; n; 1; m; 1; U1; 1; U2; 1; U3; 1; xi

6

 

0

 

7

 

-(2/3)*K1[0]/K0[7]

 

0

 

0.1555555555e-3/K1[0]

 

xi

(1.2.6)

for m to MM do for n to MM do dsys := {diff(S[m][n](t), t, t, t)+xi^2*[m]*(diff(S[m][n](t), t, t))+(-U1*U2+`&eta;__&eta;__n__`^2)*(diff(S[m][n](t), t))+xi[m]^2*`&eta;__&eta;__n__`^2*S[m][n](t) = -(2*U2*bb[m]/(Pi*xi[m])*(-BesselJ(0, xi[m]*b)/BesselJ(1, xi[m]*a)))*q+xi^2*[m]*U3} end do end do; sol := dsolve(dsys)

Error, (in StringTools:-IsPrefix) second argument must be a string

 

 

NULL

for m to MM do for n to MM do dsys2 := {diff(Q__mn(t), t, t, t)+xi[m]^2*(diff(Q__mn(t), t, t))+(-U1*U2+eta__n^2)*(diff(Q__mn(t), t))+xi[m]^2*eta__n^2*Q__mn(t) = -2*BesselJ(0, xi[m]*b)*U1*U2*b__m*(1-exp(-xi[m]^2*t))/(BesselJ(1, xi[m]*a)*Pi*xi[m]^3)} end do end do;

sol2 := dsolve(dsys2)

Error, (in dsolve) invalid input: `PDEtools/sdsolve` expects its 1st argument, SYS, to be of type Or(set({`<>`, `=`, algebraic}), list({`<>`, `=`, algebraic}), `casesplit/ans`(list, list)), but received [{Q__mn(t)*pochhammer(1-n, n)+(1497143767/5000000)*(diff(Q__mn(t), [`$`(t, t)]))+eta__n^2*(diff(Q__mn(t), t))+(1497143767/5000000)*eta__n^2*Q__mn(t) = 0}]

 

``

NULL

NULL

 

Download Kernel4.mw

Hi

First question is, given a list of some positive integers, how can I normalize this list? Normalize here is in the sense that, for example, if 

L := [1,3,4,4,5,7,7,7,8]

then there really are only 6 different integers appear, so I would like to assign each part an integer from 1 to 6 in ascending order. So 1 becomes 1, 3 becomes 2, 4 becomes 3, 5 becomes 4, 7 becomes 5 and so on. Normalized list will be

NormalizedL := [1,2,3,3,4,5,5,5,6]

 

Second question is given a list, let's say [1,3,1,3,2,2,4,4], how can I normalize it in a similar way but now we assign each integer upon occurrence of a part. So [1,3,1,3,2,2,4,4] will be [1,2,1,2,3,3,4,4]. This is necessary for me because lists have repeating parts. 

Another example will be [2,4,4,1,2,2,3,3] will be [1,2,2,3,1,1,4,4]. 

Thank you 

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