I want to model this game (I want an ensemble average and a time average)

50% chance you get head=win 50%
50% chance you get tails= lose 40%
Starting capital =100

First of all I need a very large binary matrix(1..100000,1..100000) however not
even that I can do fast enough in maple!

I tried:

rtable(1 .. 1000, 1 .. 2000, frandom(0 .. 1, .5), subtype = Array, datatype = float[8], fill = [0, 1])

it is somewhat fast but it does not do what I want ie binary ...

I'm trying to solve the following

> de := proc (omega, l, M) options operator, arrow; diff(y(r), `$`(r, 2))+(2*r-2*M)*(diff(y(r), r))/(r*(r-2*M))+(omega^2*r^2/(r-2*M)^2-l*(l+1)/(r*(r-2*M)))*y(r) = 0 end proc;

How to use maple get the nth term of sequence A: 7 + 77 + 777+ ... to n terms.

please help me!!

Thanks!

I am trying to fit some data to a model.

The model is given by this equation.

A*(C/B)^(2*B)*(B-1)^(2*(B-1))/(205*10^9*(2*B+1)*(sigma^2-(650*10^6)^2)*sigma^(2*(B-1)))+(C-sigma)^2*A/(205*10^9*(2*B+1)*(sigma^2-(650*10^6)^2))

> with(Statistics);
> X := Vector([819.4, 795.6, 788.8, 782.0, 776.56, 763.64, 748.28, 724.42, 717.40, 711.28, 707.20, 680], datatype = float);
> Y := Vector([5.3*10^4, 7.8*10^4, 9*10^4, 9.5*10^4, 10^5, 1.2*10^5, 1.37*10^5,...

hello,

I have been asked to show that the parametric representation of this curve is given by 

x(t)=cost/1+sin²t and y(t)=sintcost/a+sin²t.

The curve is defined by (x²+y²)²=x²-y² 

The polar representation of this curve is given by r²=cos(2theta)

Help!

Thankyou

I need to make one "DensityPlot-point" (similar Statistics [DensityPlot] or histogram in 

Matrixplot) of a set of points (x, y). 

The set of points (x, y) was generated by the procedure.

Is there a way to generate it?

Thank you.

I'm trying to understand the various ways to do pattern matching. The problem is that sometimes the patterns seem to matched against a normal form that's different from the one displayed. For example can somebody explain to me why the last pattern match fails below?

> patmatch((1/2)*Zeta+(1/3)*Zeta^5, conditional(Zeta^n::posint*y::anything+z::anything, n >= 3), 's'); s;
true
[n = 5, y = 1/3, z = (1/2)*Zeta]
> patmatch(Zeta^2+(1/3)*Zeta^5, conditional...

Thank you for Assisting me to solve the PDE, Now please would you tell me what F5 means (in other words, explain to me the solution) and also could you how to test if the solution satisfies the initial and boundary conditions.

Please help me plot the graphs of the following equations:-

eq1 := diff(E[X(t)], t) = lambda-delta*E[X(t)]-beta*E[X(t)*V(t)];

 eq2 := diff(E[Y(t)], t) = -delta*E[Y(t)]+beta*exp(-rho*tau)*E[X(t)*V(t)];
                                                    
eq3 := diff(E[V(t)], t) = gamma+N*kappa*E[Y(t)]-mu*E[V(t)]-beta*E[X(t)*V(t)]

NB:- E[X(t)]= the expected value of variable X at time t. 

Please help me know how to input this...

> restart;
> with(LinearAlgebra);
> tolerance = 10^(-3); x1km1 := 0; x2km1 := 0; x3km1 := 0; for k to 2 do k := k; x1k := 1/4*(5-x2km1+x3km1); x2k := 1/3*(-4+x1km1-x3km1); x3k := 1/5*(1-2*x1km1-2*x2km1); evalf(x1k); evalf(x2k); evalf(x3k) end do;
                               1
                               5
                               -
                               4
                               -4
                               --

q1.mw

This equations should have numerical solution, but they can’t be calculated. The result is too long, and include ‘RootOf’

It just like this:

> t := 15000; S := solve({n = b+2*c+f+2*g, (a+b+c)/(a+b+c+p+q+f+g) = 5*(1/10), q^2-3.47*p*10^27*t^(3/2)*e^(-10.97*10^4/t) = 0, n*b-(2.407*a*10^21*8)*t^(3/2)*exp(-18.27*10^4/t) = 0, n*c-(1/2)*(2.407*b*10^21*5)*t^(3/2)*exp(-32.035*10^4/t...

Regards,

I need help with solving an equation. I have the following equation:

24*b[0]+24*b[1]*xi+24*b[2]*xi^2+(2*(-12+24*xi))*(b[1]+2*b[2]*xi)+(2*(-12*xi+12*xi^2))*b[2]+P[cl]*L^2*(-12*xi+12*xi^2)

to this equation I applied the comand: series(%,xi) and as a result obtained:

24*b[0]-24*b[1]+(72*b[1]-72*b[2]-12*P[cl]*L^2)*xi+(144*b[2]+12*P[cl]*L^2)*xi^2

My question is: the way to solve this equation in the manner I need is setting the coefficients...

Hi, experts

I have an array which is empty, say

f:= []:

is there away to check if it's empty? I want to do something like in Matlab:

if isempty(f)

......

end

Many thanks

Kyle

Hi together,

i wanted to assume the sequence term A(n) of the first Perrin-Pseude-Prime n = 271441.

It´s not that difficult, but i do not understand the Maple-output, and i´ve never found an explenation for it.

the input was: > MatrixVectorMultiply(M^90480, v);  --> its the Matrix formula for the recurrence.

the output gives me a vector (3x1) with the following entry in the second line (witch is the line i want to know):

Hello colleagues! :)

I have some problems after create two objects, with array row in object definition...

The result - two same object...