Chia

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These are questions asked by Chia

Hi all,

I want to design a procedure which can generate multiple loop automatically. While I  assign a value to it, it will create a multiple loop with same number of layers.    

For example,

P(1):

for i from 1 to n do
...
end do:

 

p(2):

for i from 1 to n do

for j from 1 to n do
...

end do: end do:

 

p(3)...

p(4)...

...

 

 

 

I'd appreciate any help on this topic. Thank a lot.

 

Hello everyone,

I'm using Maple18, I tried to integrate the function including natural logarithm:

 

But we get the answer:

Is there any simple way to directly convert the answer to the kind of form we want? I cannot not finish the conversion:

 

So the toolbox "IntegrationTools" was used, but finally, we couldn't compute the integral:

 

 However, we can get the correct answer by manually inputting the formula.

 

Using IntegrationTools is pretty nasty and not very convenient, such as the problem I mentioned.

Does anyone have another solution?

Hello everybody,

I want to find all of roots of the complex variables functions in two ways.

(1) find the value which can make the function equals 0

(2) find the real value and imaginary value which make real part and imaginary part of function equal 0

(I know answers of these two case is not equal completely.)

 

The function is a non-linear function, including sin, cos and Bessel function, such as:

 


And, I used Analytic and fsolve to do case (1) and (2), but failure. The follow result is how I tried to find the real value answer:

 

It seems that both of two commands can only find some of roots. 

How to find all of roots of these cases? The related .mw file is attached.

Cannot_find_all_of_roots.mw

 

Thanks a lot.

 

Dear all,

I tried to use pdsolve to solve the parabolic pde but get the unexpected answer:

Is it the PDESolStruc or the other structure? Where can I find the description about this kind of structure.

Thanks.

Dear all,

It's very convenient to define a DE or PDE through Differential Operator D, for example,

((D[1, 1]+D[1, 2]+D[2, 2])(z))(x, y) = exp(x)*sin(y)

Is it possible to realize Inverse Operator Method of Operator D? How to solve the following equation if we rewrite the pde through inverse operator method?

(z)(x, y)=((D[1, 1]+D[1, 2]+D[2, 2])^(-1))exp(x)*sin(y)

 

Thanks a lot.

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