guras

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11 years, 160 days

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These are questions asked by guras

 

I am using Maple 15, and before that Maple 8 and Maple 13. While using the versions 13 and 15, 

I come across with this problem; I cannot copy an output and use it as input. In Maple 8, I was able to do this but in 

these improved versions, it seems that it is not possible. Is there a way to solve this problem? I saw some answers about this

problem suggesting to change launch.ini file. But I could not apply this suggestion, since it is not permitted by the system. 

 

 

Assume that I have r:= -6x+3y+23x2-4xyz+7z. By using coeffs(r,x,'k') I can find the coefficients of 1, x, and x2

What should I write to get the conditions that make the coefficient of x zero? How can I just pick the coefficient of x, and solve it. 

I have several coefficients but the answer of this question will help me. 

 

Thanks.

I want to solve the int((y4+by2+c)-1/2,y)-x and find y=h(x), where b and c are constants s.t. c>b2/4. Maple gives me complex Jacobi elliptic function as a result. But I am not sure that this integral has complex value. Am I doing something wrong or the result is really a complex valued function? Thanks.

Indeed my main question is: Plot y=y(u) where we have these two relations: int((y4+by2+c)-1/2,y)=x and find y=h(x). Then evaluate int((h(x)-B)-1/2,x)=u and find x=g(u). By using these relations plot y=y(u). :)

Here B is an arbitrary constant, but if necessary we can define a value for it. All the variables and constants are real.

I hope I manage to express myself. Thanks again.

 

I want to plot a function f(v). But I could not find the explicit form of f(v). I know the function f(u) where u satisifies the relation int(h(u),u)=v for known function h(u). But unfortunately, Maple could not help to solve the integral i.e. I could not find u in terms of v. Under these conditions, is it possible to plot f(v) by using Maple?

Thanks.

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