manjees

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Hi all, I have this same equation in another active thread also with boundary conditions. But now I have INITIAL CONDITIONS INSTEAD. I thought of just starting a fresh post. Here is my non-linear differential equation x := diff(y(r), r, r)+2*(diff(y(r), r))/r+ C*polylog(3/2, -exp(C2*(C3-y(r)))) = 0 with boundary values D(y)(0)=0 and y(0)=0. C, C1 and C2 are some numbers. The hint says to use procedure to solve polylog and then integrate the differential equation. I was wondering if I can get some advice on solving this equation.
Hi all, I have a non-linear differential equation x := diff(y(r), r, r)+2*(diff(y(r), r))/r+ C*polylog(3/2, -exp(C2*(C3-y(r)))) = 0 with boundary values D(y)(0)=0 and y(infinity)=0. The hint says to use a subroutine to solve polylog and then integrate the differential equation with help of a Runge-Kutta like scheme. I was wondering if anyone could help me with this. I have no clue how to use subroutines and specially when y(r) is within polylog. Thanks in advance, MS
Hello everyone, I was wondering if I can get some advice on solving two integral equations given below for u and b. y(r) is parametrically dependent on 'u' and 'b'. l := -C1*(int((3*polylog(5/2, -exp(b*(u-y(r))))/b^(5/2)+y(r)*polylog(3/2, -exp(b*(u-y(r))))/b^(3/2))*r^2, r = 0 .. 10.))-C2=0; I2:=C3*(int(r^2*polylog(3/2, -exp(b*(u-i))), r = 0 .. 10.))/b^(3/2)-1=0; where C1,C2,C3 are numbers and y(r) is parametrically dependent on 'u' and 'b'.
Hi, can some one help me solve this differential equation. diff(y(r), r, r) = -2*(diff(y(r), r))/r-1.910049266*10^5*polylog(3/2, exp(-0.4813739e-1+0.203e-2*y(r))) the boundary conditions are: y(infinity)=0, Dy(0)=0 Thank you MS
Hi all, thanks for all the help so far. I have this nonlinear differential equation with boundary conditions. I have tried quite few ways but nothing has worked so far. x := diff(y(r), r, r)+2*(diff(y(r), r))/r+1.5*(16*4300)*Pi^2*10^6*sqrt(Pi/(2*0.128e-2^3))*polylog(3/2, exp(0.128e-2*(1194.3-y(r)))) = 0; boundary conditions: bc:= D(y)(0) = 0, y(infinity) = 0 Thanks in advance MS
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