paulmcquad

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These are questions asked by paulmcquad

How do i plot / graph a limt? The plot must have a hole at 2 because it is undefined.

limit((x^2-1)/(x-1), x = 1) = 2NULL

``

Download graph-a-limit.mw

I was trying to look for an easy way to plot the locations of the distance and midpoint on a graph. I found how to get the distance and midpoint functions but plotting them is hard.

Thanks in advance.

 

with(Student:-Precalculus)

with(Plot)

a := [1, 3]

b := [5, 6]

Distance(a, b)

5

(1)

Midpoint(a, b)

[3, 9/2]

(2)

Line(a, b)

y = (3/4)*x+9/4, 3/4, 9/4, -3

(3)

Line(a, b, output = plot)

 
 

 

Download How-to-plot-distance-midpoint.mw

Is there an easy way to get the midpoint and distance in maple?

Thanks in advance.

Distance and Midpoint

 

 

Table 1: Key Skills

NULLdmf1 := [-3, 1]

[-3, 1]

(1)

dmf2 := [3, 2]

[3, 2]

(2)

dmf3 := [-2, -3]

[-2, -3]

(3)

dmf4 := [3, -2]

[3, -2]

(4)

dmf := [dmf1, dmf2, dmf3, dmf4]

[[-3, 1], [3, 2], [-2, -3], [3, -2]]

(5)

plot(dmf)

 

NULL

dme1a1 := [1, 3]

[1, 3]``

(6)

dme1a2 := [5, 6]

[5, 6]

(7)

dme1a3 := [5, 3]

[5, 3]

(8)

dme1 := [dme1a1, dme1a2, dme1a3]

[[1, 3], [5, 6], [5, 3]]

(9)

plot(dme1)

 

NULL

``

NULL

NULL

NULL

NULL

NULL

NULL

NULL

Download 2.1-Distance_and_Midpoint.mw

Can maple simplify a Combined Inequality? At best it outputs imho a more complicated solution.

Thanks in Advance.

sl10 := -1 <= (3-5*x)*(1/2) and (3-5*x)*(1/2) <= 9

0 <= 5/2-(5/2)*x and -(5/2)*x <= 15/2

(1)

The output should be:

 

-3 <= x and x <= 1


Download Combined_Inequality.mw

Is there a way to put in intervals and get the output as inequality Notation? Something like this ->

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