@Thomas Dean 

Why do you talk about Maplet and where the message in your initial question comes from?
I don't see any Maplet command  in your code.

There is no Maple restriction.

But having already encountered this problem in my professional activities I can tell you that since Windows10 such a limitation is imposed by the OS (and defined by the value [that you can change] of variable MAX_PATH).
Neither Mac OSX not Linux impose a limitation to the lenth of a path.

First point: replace your last line by this one

obj := add((stress[i]-true_stress[i])^2, i = 1 .. 10)

Next it would be usefull you provode ranges of variation for the seven parameters (G1,G2,G3,tau1,tau2,tau3, strain) for a crude attempt to minimize obj lead to non numeric values.

@Ahmed111 

You will find in the attached file:

• A correct construction of M (if I'm not mistaken).
   
• A synthetic representation of its characteristic polynomia (formula (6), valid for any value of N).
   
• The expression CharacteristicPolynomial provides and a few ways to express this lengthy formula in a more synthetic form (while less tractable than (formula (6))

Download CP_2.mw

@Ahmed111 

I'm sorry, I didn't see the comma in

diag(-2*lambda, a)

and read

diag(-2*lambda . a)

To get the matrix you want  you have to write (a being a vector of size N) write

M11 := DiagonalMatrix( < -2*lambda, V(n, a) > )

Nevertheless you need to me more precise: what is exactly the shape ofthe matrix M you want to build (write it by hand for N=2 to provide an example)?

A few interpretations are fiven in the attached file (each corresponds to an input text of different color)
Whatever, assuming c has length N+1, here is a correction (inputs in black at the end of the file)
CP.mw

@Hahn Hahn 

Look here to see how you can check your inputs Check_your_inputs.mw
(as I use an "old" version of Maple I had to write g := (x,q) -> ... for it doesn't accept your syntax)

@Thomas Richard, please excuse me for intervening.

@sursumCorda 

With the linalg package the eigenvectors are returned this way

linalg:-eigenvectors(m);
                   [-1, 1, {Vector[row](2, {(1) = -1, (2) = 1})}], [7, 1, {Vector[row](2, {(1) = 1, (2) = 1})}]

But for the LinearAlgebra package you get a vector of eigenvalues and the matrix of eigenvectors.
If you set _EnvLinalg95 to true, use the option output='list' in  LinearAlgebra:-Eigenvectors (which then returns the eigenvectors under the form linalg-eigenvectors does):

_EnvLinalg95 := true:
LinearAlgebra:-Eigenvectors(m, output='list');
[[7, 1, {Vector(2, {(1) = 1, (2) = 1})}], [-1, 1, {Vector(2, {(1) = -1, (2) = 1})}]]

You have 3 indeterminates (x, y, z) and 2 equations (notice there is no f nor g as you say in the text).
Could you be more precise?

@Carl Love 

I tried hard, not enough obviously, to prove the equality by hand.

For the record the left hand side of rel(n) is a consequence of another relation, one can get on several papers, which is said to be "true for all integers larger than 3".
I observed it was also true for n=2, for any negative integer... and for any real number but 1 (so what is it to write the previous sentence?).
This puzzled me and then started simplifying rel(n), rewritting some terms differently and so on, thinking that assume/assuming would be of no help.
Thanks again for this Martin Gardner's Ahah intuition.

@acer @vv

Thanks to both us for your quick reply.

@Carl Love 

Sorry, I missed it.
But its notations remain confusing, not to say meaningless.

@Rouben Rostamian  

ContoursWithLabels is Kitonum's code see_here

@C_R 

Thanks for your return.

Go here help(dsolve[numeric]), search for 'known', try to understand hot to proceed from examples dsol8 and dsol8b.

@Muhammad Usman 

Does this suit you?

plots[display](
  PP
  , size = [500, 400]
  , axis[1]=[tickmarks=[seq(k=k/10., k=0..20, 5)]]
  , axis[2]=[tickmarks=[seq(k=k/10., k=0..20, 5)]]
);

But given L=1 and T=2, it seems to me that this

plots[display](
  PP
  , size = [500, 400]
  , axis[1]=[tickmarks=[seq(k=evalf(k*`&Delta:x`), k=0..20, 5)]]
  , axis[2]=[tickmarks=[seq(k=evalf(k*`&Delta:t`), k=0..20, 5)]]
);

would be more correct.

What is the structure of the data you want to send to Tecplot?
I guess it is a collection of contours, each contour being a collection of segments, that is a collection of 2x2 matrices.
The question is what structure Tecplot can manage? Once defined, the corresponding structure can be build in Maple.
But the "precision" of a contour of a given length is defined by the number of segments which approximate this contour. So the drawing in Tecplot of a contour made of, for instance, 100 segments constructed in Maple, will not have an higher resolution than thesame contour directly drawn in Maple.