Maple 18 Questions and Posts

These are Posts and Questions associated with the product, Maple 18

How to plot Complex vales in 2D? 

Z be complex.

rho := 1/4; mu := 1/4; E := sum(Z^k/GAMMA(k*rho+mu), k = 0 .. 5)

How to solve and plot the integral equation?
b.mw
 

Is it possible to solve DE without initial conditions
(1/24)*exp(-8)-(1/12)*exp(-5)+(1/24)*exp(-2)-(1/24)*exp(-10)+(1/24)*exp(-9)+(1/24)*exp(-1)+diff(f(x), x, x, x, x, x)+d*(diff(f(x), x))+e*f(x)+a*(diff(f(x), x, x, x, x))+b*(diff(f(x), x, x, x))+c*(diff(f(x), x, x))-1/24

where, a, b, c, d, and e are constant coefficients.....

How to solve and plot DE?

eq1 := diff(f(x), `$`(x, 5))+2*(diff(f(x), `$`(x, 4)))+diff(f(x), `$`(x, 3))+diff(f(x), `$`(x, 2))+2*(diff(f(x), `$`(x, 1)))+3*f(x) = g(x)

Download MHD1.mw

 

 

System of equations with boundary conditions are moving?

Also, find the values of unknown variables?

Dear maple users 

Greetings.

In this code, I am solving the PDEs via perturbation method.

There is some mistake in the boundary condition and pdsolve.

Kindly help me that to get the solution for this PDE via perturbation method.

Wating for your replay.

BC: 

Code: JVB.mw

eq1 := diff(h(t), [`$`(t, nu)])+(1/4)*h(t) = 8/3*(1/(sqrt(Pi)*t^(1/2))-(3/32)*t^2+(3/16)*exp(-t)-1);


with ics h^k (0)=0 for k=0..n

how are please I want to help In some graphs in maple 

the graph in the picture

thank you 

)


 

Download analy_numer.mw

 

 

Hello,
I am trying to compute the convolution integral numerically and compare the result with the analytic result. My numerics is giving terrible results:

clc;clear;
% Define i1(t) and i2(t) as symbolic variable
syms i1(t) i2(t)

% Given differential equation
ode1 = diff(i1) == 0.5*i1 + -3*i2 +5*exp(-2*t);
ode2 = diff(i2) == 2*i1 - 6*i2;
odes = [ode1; ode2];

% Define initial conditions
cond1 = i1(0) == 1;
cond2 = i2(0) == -1;
conds = [cond1; cond2];

% Solution of system of differential equation
[i1(t), i2(t)] = dsolve(odes,conds)

fplot(i1(t))
hold on
fplot(i2(t))
legend('i1(t)','i2(t)')

Output:

i1(t) =
exp((t*(73^(1/2) - 11))/4)*(73^(1/2)/8 + 13/8)*((57*73^(1/2))/292 - exp((3*t)/4 - (73^(1/2)*t)/4)*((15*73^(1/2))/292 + 5/4) + 3/4) - exp(-(t*(73^(1/2) + 11))/4)*(73^(1/2)/8 - 13/8)*(exp((3*t)/4 + (73^(1/2)*t)/4)*((15*73^(1/2))/292 - 5/4) + (3*73^(1/2)*(73^(1/2) - 19))/292)


i2(t) =
exp(-(t*(73^(1/2) + 11))/4)*(exp((3*t)/4 + (73^(1/2)*t)/4)*((15*73^(1/2))/292 - 5/4) + (3*73^(1/2)*(73^(1/2) - 19))/292) + exp((t*(73^(1/2) - 11))/4)*((57*73^(1/2))/292 - exp((3*t)/4 - (73^(1/2)*t)/4)*((15*73^(1/2))/292 + 5/4) + 3/4)

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