Hello! I have the task to calculate the two angles of an 3d linkage. now in step 11 i have these two equations:

I have to solve these for phi, that is the angle I'm looking for. But the solution for phi should be indepented of psi. alpha and beta are variables. Everything else are known constant values.
What I tried: I solved Gl7 for psi (step 12...

Can someone please solve only #19 and #25 using Nwton's method in Maple. I really appreciate it.

The questions are attached. Thank you

An intersection in my neighbourhood, currently controlled by a 2-way stop, is under consideration to become a 4-way stop.  This means the traffic that currently has the right-of-way will be required to come to a complete stop, wheras previously they could have coasted down the hill, and accelerated up the other side.   Politics aside, I was curious to explore the following question:

You have been asked to design a one-liter can shaped like a right circular cylinder. What dimensions will use the least material?

-I really need help on how to correctly plug this into my computer. Thank you in advance.

> Q;       

[                 3                           ]       

[1 - h121 - h124 y  - h124 y - h125 x + h125 y]

> rtable_num_elems(convert(Q, list));

Error, rtable expected

> rtable_num_elems(Q);

Error, rtable expected

https://skydrive.live.com/redir?resid=E0ED7271C68BE47C!341

1*2 Vector has nops should be 2

but

it show 3

Hi all,

#####################################
myp:=proc(a,b,c)

local ans;

ans:=zip(`+`,a,b);

ans:=ans*c;

return ans;

end proc;
myp([$1..4],[x,y,z,w],2);
map2(myp,[$1..4],{[x,y,z,w],[x2,y2,z2,w2],[x3,y3,z3,w3]},4);

map2(myp,[$1..4],{[x,y,z,w],[x2,y2,z2,w2],[x3,y3,z3,w3]},10);
map2(myp,[$1..4],{[x,y,z,w],[x2,y2,z2,w2],[x3,y3,z3,w3]},0.5);

#####################################

Is it possible to use something like

Given an n*n matrix M an its rth row and cth column element m[r,c].Suppose m[r,c] = c*m[r-1,c]+a*m[r-1,c-1] and m[0,0]=1, m[0,k]=m[l,0]=0 for k>0,l>0.The letter "a" denotes a constant number and n can be any non negtive integer.

Hi all,

##################################################################

restart:

K:=50;C:=20;

st:=time():

    for j from 2 to K do
        for c to C do
            solve({log(cat(p,j,'C',c)/(1-cat(p,j,'C',c)))=mu+cat(tau,j)+cat(eta,c)+cat(mix,j,c)},cat(p,j,'C',c));
            assign(%);
  ...

In 2D, graph a blue ellipse x(t)=3cos(t), y(t)=2sin(t) for 0≤t≤2∏. For t=0.5 graph a green tangent line to the ellipse and a red osculating circle. Also, give the curvature, the equation of the tangent line and the center of the osculating circle

Hi,

I have this system of lienar equations:

If I have the parameters-(v,k,lambda) of a combinatorical design, I wonder whether I can get the incidence matrix of the design or not with maple.

Remark:v is the number points of the design; k is the number of points on each line; lambda is the number of points common on every two lines.

Thanks!

Hi, I'm trying to find the first ten roots of the equation:

sin(a*Pi)*sqrt(4*a^2+3)*cos(sqrt(4*a^2+3)*Pi)+sin(sqrt(4*a^2+3)*Pi)*a*cos(a*Pi) = 0

But fsolve only finds one root, and not necessarily the first one. So I'm having a difficult time getting the first 10 roots without preknowledge of the intervals to search in. (I can obviously plot it, but there are some other parameters which affect this equation and I can't manually find the intervals every time I change them).

I've a problem with the buttons. It's not a problem to make a line break, but if I reload or change the text into my button (while the program ist running) maple/maplets ignores all line breaks.

Here is an small example (maybe not the best):

with(StringTools):
with(Maplets[Elements]): ToGreen := proc()
Maplets:-Tools:-Set(B(caption) = "blue\nhallo");
end proc:

maplet := Maplet([   

g1 := Vector([0, y, x]);

g2 := Vector([0, y^2-x-y, 0]);

g3 := Vector([x, x+y, 0]);

g4 := Vector([y, -y, 0]);

g5 := Vector([0, x*y+x/2+y/2, 0]);

g6 := Vector([0, x^2-x/4-y/4, 0]);

[g1, g2, g3, g4, g5, g6]

cc := [Vector(3, {(1) = 0, (2) = y, (3) = x}), Vector(3, {(1) = 0, (2) = y^2-x-y, (3) = 0}), Vector(3, {(1) = x, (2) = x+y, (3) = 0}), Vector(3, {(1) = y, (2) = -y, (3) = 0}), Vector(3, {(1) = 0, (2) = x*y+(1/2...