The function

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These are questions asked by The function

Hello, ive got another question. Im in the last chapter of this book, and i hope i can finish the book this month. So i can start with part 2 of the series of applied math for higher job education. The first book is basically the freshmans year worth of math, and im completing it within 2 months. So im happy with that. :) 

Okey here is the question: 
a.
Draw half a circle x^2+y^2=4, with y >= (bigger or equal to) 0. 

So how do i make half a circle instead of the whole circle? 

The rest of the text says:
b.
Which body is created if the area bordered by the x-axis and this half circle is revolved around the x-axis?
c.
Calculate the volume of this body. 

Greetings,

The Function

smartplot(x^2+y^2 = 4)

 

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Download Question_for_maple_primes_7.mw

Hello everyone!

I made an integration and it gave me a really long answer. The answer of the book is the same, as you can see, i "smartplotted" the two answers, and they are the same. But how do i get the nice short answer? I tried a lot of different things, but nothing gave me that short answer. 

I would really like to be able to get nice short answers, while it will really clean things up. 

Thank you!

Greetings,

The Function

int((v^2-1)*(v^3-3*v+6)^5, v)

(1/18)*v^18-v^16+2*v^15+(15/2)*v^14-30*v^13+180*v^11-(585/2)*v^10-300*v^9+1539*v^8-1350*v^7-(4239/2)*v^6+5994*v^5-4050*v^4-3888*v^3+9720*v^2-7776*v

(1)

NULL

"f(v):=1/18 v^18-v^16+2 v^15+15/2 v^14-30 v^13+180 v^11-585/2 v^10-300 v^9+1539 v^8-1350 v^7-4239/2 v^6+5994 v^5-4050 v^4-3888 v^3+9720 v^2-7776 v"

proc (v) options operator, arrow, function_assign; (1/18)*v^18-v^16+2*v^15+(15/2)*v^14-30*v^13+180*v^11-(585/2)*v^10-300*v^9+1539*v^8-1350*v^7-(4239/2)*v^6+5994*v^5-4050*v^4-3888*v^3+9720*v^2-7776*v end proc

(2)

"f1(v):=1/(18)*(v^(3)-3 v+6)^(6)"

proc (v) options operator, arrow, function_assign; (1/18)*(v^3-3*v+6)^6 end proc

(3)

smartplot(f(v), f1(v))

 

(1/18)*v^18-v^16+2*v^15+(15/2)*v^14-30*v^13+180*v^11-(585/2)*v^10-300*v^9+1539*v^8-1350*v^7-(4239/2)*v^6+5994*v^5-4050*v^4-3888*v^3+9720*v^2-7776*v

(1/18)*v^18-v^16+2*v^15+(15/2)*v^14-30*v^13+180*v^11-(585/2)*v^10-300*v^9+1539*v^8-1350*v^7-(4239/2)*v^6+5994*v^5-4050*v^4-3888*v^3+9720*v^2-7776*v

(4)

(1/18)*(v^3-3*v+6)^6

(1/18)*(v^3-3*v+6)^6

(5)

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Download Question_for_maple_primes_6.mw

Hello everbody! 

Ive got a question about my dutch math book, and why it thinks its answer is better than mine. 

It is question c. the integral that is covers the x value from 4 to 6 for f(x). 

I would think that means the integral of 1 to 6 - the integral of 1-4, and thus 4-7=-3. Now i dont know how they thought about getting a smaller area under the function with a larger domain of x, so i am not sure what is going on. Im not even sure if what they ask is possible. The book gave 3 as an answer. My answer was -3. Looking at it, and thinking about it. It may not even be possible. 

Any way, that is the question. 

Picture 2 shows the rules, picture 3 shows the answers of the book. 

Thank you!

Greetings,

The function

Opdracht 2
a.

0

b.

-7

c.

4-7

-3

(1)

d.

8*5

40

(2)

e.

int(5, x = 1 .. 6)+4

29

(3)

f.

3*4-6*5

-18

(4)

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Download Question_for_maple_primes_5.mw

Ive got new "problems" with my math book. This time it is about differentiating like Gottfried Wilhelm Leibniz (https://en.wikipedia.org/wiki/Gottfried_Wilhelm_Leibniz), and his Leibniz notation.  (https://en.wikipedia.org/wiki/Leibniz%27s_notation).

dx/dy. Now that does sound like its just f'(x), of function f(x). But now they wanted something else i cannot produce. I could do the examples, and try to work it out like, but "im here to learn maple, not how to get my hands filthy with ink, and scratch on the paper when i make mistakes"... :P 

It says: Determine the differential that is being asked. 

No matter what i do, there wont be any solution that looks like the one given by the book. 

I would like to be good at this, while a lot of old books do still have the Leibniz notation. So it is eccential to be good at this if you want to really study the origins of math and science. 

Thank you!

Greetings,

The Function

Hello, i stumbled across a function that does not want to plot regularly.

The translation: The tension U(t) (in volts) measured across a resistance in a electric circuit is given by U(t)=cos(2t)*U*e^t/10.

a. Plot the graph of y=U(t)
b.Calculate the limit t->infinity and acquire the horizontal asymtote of the graph of y=U(t). 
c. Calculate the intersecting points of the graph of U with horizontal asymptote (dont ask me how, while how can a function intersect with its own asymptotes??). 

So the question actually is how to graph this function?
Maybe then i can make up from that how the function intersects with its own asymptotes.

Thank you!

Greetings,

The Function.  


"U(t):=U*(e)^(-(t)/(10))*cos(2* t);smartplot(U(t));"

proc (t) options operator, arrow, function_assign; U*exp(-(1/10)*t)*cos(2*t) end proc

 

 

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Download Question_for_maple_primes_4.mw

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