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6 years, 264 days
Maple is to me difficult. The first version I bought was Maple9, and it was more than 15 years ago. But, I couldn't use it, feeling it too difficult. But, three years ago, I thought Maple might be helpful to my study, and since then, I have continued to learn Maple. As I got able to read the Maple help, I think that I could get to use maple better now than before. But, I feel that I am a beginner yet.

MaplePrimes Activity

These are questions asked by taro

A Happy New Year, people in mapleprimes,

I have a question, but this might be an inappropriate question to this site.

In Introduction to Maple, there is a calculation with a double square root.
Related to it, I want to calculate the following expression, which has a value of zero.


Is there any way to use maple  so as to explain how the above expression takes the value of zero?

On earth, I cannot understand why this takes zero.

I hope you will give me a hint.

Thanks in advance.


Hello people in mapleprimes,

I have a question.
I want to modify

a := rho^(epsilon-1)*a__01^(-k)*(N__E2/Omega+N__E1*mu)*(K+1)/mu;

But, I can't do that modification.

The key term is

I know how to use applyop, but even if I use it, I couldn't obtain b.

Please teach me about this.




Hello people in mapleprimes,

I want to know some way, if there is, to do the modification of the following, that is

The original expression: (beta*L__1/P)^beta*((1-beta)*L__1)^(1-beta)
The expression after modification: beta^beta*L__1*(1/P)^beta*(1-beta)^(1-beta)

I did this with freezing (1-beta) in (1-beta)*L__1.
But, this is a little long code. I will be glad if you tell me some more simple way to do this.

Thanks in advance.




Hello people in mapleprimes,

I have a problem about map.


The output of this code is not y*z/x, but  (x*y*z)^(-y*z).

I can't understand why this occurs.
Can't you teach me about this?

Thanks in advance.


Hello People in mapleprimes,


would not be simplifyed to k*a^(k-1)/a__0^k


symplify(a^k*k/(a*a__0^k)) assuming(k>1);

or other commands including expand.

Is there any way other than simplify(numer(..)/a)/simplify(denom(..)/a); ?

Thanks in advance.


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