taro

470 Reputation

12 Badges

8 years, 13 days
Maple is to me difficult. The first version I bought was Maple9, and it was more than 15 years ago. But, I couldn't use it, feeling it too difficult. But, three years ago, I thought Maple might be helpful to my study, and since then, I have continued to learn Maple. As I got able to read the Maple help, I think that I could get to use maple better now than before. But, I feel that I am a beginner yet.

MaplePrimes Activity


These are questions asked by taro

Hello people in mapleprimes,

I want to modify the following expression a to b. For it, I used c code.
But, as seen in d, just using c returns a. Originally, I intended phi being between 0 and 1, so
that 1-phi >0. Isn't any better way to modify a to b? and it is better to have maple sort expression remembering 1-phi to be positive, and to have maple give any priority to it in modifying a to b.

a:=(-2*theta+1)*phi/(phi-1)+theta;
b:=(2*theta-1)*phi/(-phi+1)+theta;
c:=simplify(-1*numer(op(1,aa)))/simplify((-1)*denom(op(1,aa)))+theta;
d:=simplify(c)
(-2*theta+1)*phi/(phi-1) + theta

I will be very glad if you borrow me your idea.

Thank you in advance.

In Kitonums'answer of

http://www.mapleprimes.com/questions/220229-How-Do-I-Solve-A-Differential-Equation-In-Maple

I read a code of remove(t->t=".", b);
t->t="." is a Boolean-valued procedure.

But, then, why does (t->t=".")(9); not return false like (t->t^2)(3); returns 9?
How can I have maple return false?

Thanks in advance.

Hello people in mapleprimes,

I have an expression, which apparently can be factored with (beta-1)

e1 := -(beta-1)*L*s*lambda*Omega^3+(beta-1)*L*s*g^k*epsilon*(T*lambda-T+1)*Omega^2+(beta-1)*L*s*(T+lambda-1)*Omega-(beta-1)*L*s*g^k*T*epsilon*lambda;

I want this expresson factored with (beta-1) but keeping other terms the same as

e2:=-L*s*lambda*Omega^3+L*s*g^k*epsilon*(T*lambda-T+1)*Omega^2+L*s*(T+lambda-1)*Omega-L*s*g^k*T*epsilon*lambda;

Is this possible?

I hope you will help me for this.

Thanks in advance.

taro

question_q1_11_28_2016.mw

 

 

Hello people in mapleprimes,

I hope that you will give me an answer about the calculation surrounding D.
D((x+y)^2) can be calculated with maple, but D((x+y)^a), where a is a constant, cannot at least directly.
And, I have the code, which Mr. Carl Love kindly gave me at
http://www.mapleprimes.com/questions/218045-Logarithmic-Derivative
, which is

h:= F-> expand(evalindets(D(F)/F, specfunc(D), d-> op(d)*'h'(op(d))));

This works for (x+y)^2, but does not work for (x+y)^a.
And, I think this reason is that the behavior of D to (x+y)^2 is not the same
 as that to (x+y)^a.
And, I want to modify this code.
But, I can't .
So, I am asking this question. How should I modify the above code so that it works for (x+y)^a.
I'm so sorry for a lot of impoliteness.
I will be very glad if you give me an answer.

Take care.

taro

Hello people in mapleprimes,
I want to collect
aa:=sigma*omega*alpha = mu(H, H)*s*omega*gamma*L+omega^(-sigma+1)*tau*mu(F, F)*s*L-omega^(-sigma+1)*tau*mu(F, F)*s*L*gamma;
with omega^(-sigma+1);

I know that the above expression could be collected with tau, which
produces the same expression as the one collected with omega^(-sigma).
And, in collecting with omega^(-sigma+1), I know that freeze-thaw could be used.

But, I want to know another way to do the same thing, using frontend or 
subsindets. Is this possible?

Thanks in advance.

taro
 

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