edgar

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15 years, 249 days

MaplePrimes Activity


These are replies submitted by edgar

How about first working on a simple case ... say k=0, x=0 ... then we have to do Sum((-1)^n*GAMMA(n+1/2)^(1/2)/(GAMMA(1+n)^(1/2)*Pi^(1/2)), n = 0 .. infinity) Can you do that one? The term goes to 0 very slowly, but we get convergence because it is alternating. I see no reason for a closed-form answer, though. --- G A Edgar
I am also on Mac Pro, but not Firefox, and doesn't happen with me. Perhaps Firefox has some shortcut method to open a new tab? --- G A Edgar
On my Mac I use a utility called "MenuMaster" to bind keystrokes to menu choices... --- G A Edgar
Do you have some reason to think a closed-form solution exists? --- G A Edgar
Look at the crazy answer to int(g,x) ... Now plug in infinity and -infinity and subtract, to get the answer 0. --- G A Edgar
So I tried it. JavaViewLib comes from http://www.javaview.de/maple/ Even though the web site has not been updated for two years, they mention only up to Maple 10, and do not mention Mac at all, still it worked (mostly) on my Mac with Maple 12. As a bonus ... Maple's own VRML output seems to do only VRML version 1 (which is 12 years out of date by now), but using JavaViewLib I can get VRML version 2 (aka VRML97) output files. --- G A Edgar
I read the iPhone descriptions. "Mathomatic" seems to be the most available so far. --- G A Edgar
If you have an iPhone, search "algebra" in the app store, and see if one of those does what you want. Maybe their capabilities are minuscule compared to Maple, but so are their prices! --- G A Edgar
I can't see Robert's images either ... the "alt" codes show a[n]=1/Pi*Int(f(x)*cos(n*x),x=0..2*Pi) b[n]=1/Pi*int(f(x)*sin(n*x),x=0..2*Pi) --- G A Edgar
/ Library/Frameworks/Maple.framework/Versions/12/lib so you probably need an admin password to put something there --- G A Edgar
/ Library/Frameworks/Maple.framework/Versions/12/lib so you probably need an admin password to put something there --- G A Edgar
I think he wants his result to be a formula that works for all n ... Something like this... > diff(1/(1+x^2),x$n) assuming n::posint; (n!/2)*(-exp(-(1/2)*n*ln(1+x^2))*sin(n*arctan(1, -x))*x+exp(-(1/2)*n*ln(1+x^2))*cos(n*arctan(1, -x))+exp(-(1/2)*n*ln(1+x^2))*sin(n*arctan(-1, -x))*x+exp(-(1/2)*n*ln(1+x^2))*cos(n*arctan(-1, -x)))/(1+x^2) [I hope I got that right...] --- G A Edgar
I think he wants his result to be a formula that works for all n ... Something like this... > diff(1/(1+x^2),x$n) assuming n::posint; (n!/2)*(-exp(-(1/2)*n*ln(1+x^2))*sin(n*arctan(1, -x))*x+exp(-(1/2)*n*ln(1+x^2))*cos(n*arctan(1, -x))+exp(-(1/2)*n*ln(1+x^2))*sin(n*arctan(-1, -x))*x+exp(-(1/2)*n*ln(1+x^2))*cos(n*arctan(-1, -x)))/(1+x^2) [I hope I got that right...] --- G A Edgar
* It is already implemented in Mathematica. * But what about SAGE? (I thought Sage was alec's favorite) --- G A Edgar
* It is already implemented in Mathematica. * But what about SAGE? (I thought Sage was alec's favorite) --- G A Edgar
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