Unanswered Questions

This page lists MaplePrimes questions that have not yet received an answer

How to make maple sheet background transparent?

and change word color ?

I have two list in which I need to substitute variables from on elist with variables in other list in an expression.

rootElements := [[a, Integer, c, Integer, -k*a, b], [Integer, c, a, Integer, b, -k*a], [Integer, a, b, -k*a, c, Integer], [Integer, a, Integer, c, -k*a, b]];

list1 := [[a[maximum], 0, c[maximum], 0, (-k*a)[minimum], b[minimum]], [0, c[minimum], a[maximum], 0, b[maximum], (-k*a)[maximum]], [0, a[minimum], b[maximum], (-k*a)[maximum], c[maximum], 0], [0, a[minimum], 0, c[minimum], (-k*a)[minimum], b[minimum]]]


let the term be

term :=a*c/(k*a+b);


Terms := seq(applyrule([seq(rootElements[i][j] = list1[i][j], j = 1 .. nops(list1[i]))], term), i = 1 .. nops(list1));

my outputs  are

a[maximum]*c[maximum]/(k*a[maximum]+b[minimum]),# k*a should be minimum, becuae I substituted a earlier it is failing
a[maximum]*c[minimum]/(k*a[maximum]+b[maximum]),
a[minimum]*c[maximum]/(k*a[minimum]+b[maximum]),# k*a should be maximum, becuae I substituted a earlier it is failing
a[minimum]*c[minimum]/(k*a[minimum]+b[minimum]);

is there a way to substitute larger terms first[like -k*a first] and goes to smaller variable??

 I am using applyrule since algsubs cannot do for more than one substitution.Also, I would be glad if any other alternative is provided.
thank you
 

>>> maple = pywinauto.application.Application().start(r'C:\Program Files\Maple 2015\bin.win\maplew.exe')
C:\Users\mas\AppData\Local\Programs\Python\Python36-32\lib\site-packages\pywinauto\application.py:1044: RuntimeWarning: Application is not loaded correctly (WaitForInputIdle failed)
  warnings.warn('Application is not loaded correctly (WaitForInputIdle failed)', RuntimeWarning)
>>> maple.Maple.PrintControlIdentifiers()
__main__:1: DeprecationWarning: Method .PrintControlIdentifiers() is deprecated, use .print_control_identifiers() instead.
Traceback (most recent call last):
  File "C:\Users\mas\AppData\Local\Programs\Python\Python36-32\lib\site-packages\pywinauto\application.py", line 246, in __resolve_control
    criteria)
  File "C:\Users\mas\AppData\Local\Programs\Python\Python36-32\lib\site-packages\pywinauto\timings.py", line 453, in wait_until_passes
    raise err
pywinauto.timings.TimeoutError

During handling of the above exception, another exception occurred:

Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
  File "C:\Users\mas\AppData\Local\Programs\Python\Python36-32\lib\site-packages\pywinauto\__init__.py", line 50, in wrap
    return method(*args, **kwargs)
  File "C:\Users\mas\AppData\Local\Programs\Python\Python36-32\lib\site-packages\pywinauto\application.py", line 585, in print_control_identifiers
    this_ctrl = self.__resolve_control(self.criteria)[-1]
  File "C:\Users\mas\AppData\Local\Programs\Python\Python36-32\lib\site-packages\pywinauto\application.py", line 249, in __resolve_control
    raise e.original_exception
  File "C:\Users\mas\AppData\Local\Programs\Python\Python36-32\lib\site-packages\pywinauto\timings.py", line 431, in wait_until_passes
    func_val = func(*args, **kwargs)
  File "C:\Users\mas\AppData\Local\Programs\Python\Python36-32\lib\site-packages\pywinauto\application.py", line 191, in __get_ctrl
    dialog = self.backend.generic_wrapper_class(findwindows.find_element(**criteria[0]))
  File "C:\Users\mas\AppData\Local\Programs\Python\Python36-32\lib\site-packages\pywinauto\findwindows.py", line 84, in find_element
    elements = find_elements(**kwargs)
  File "C:\Users\mas\AppData\Local\Programs\Python\Python36-32\lib\site-packages\pywinauto\findwindows.py", line 303, in find_elements
    elements = findbestmatch.find_best_control_matches(best_match, wrapped_elems)
  File "C:\Users\mas\AppData\Local\Programs\Python\Python36-32\lib\site-packages\pywinauto\findbestmatch.py", line 533, in find_best_control_matches
    raise MatchError(items = name_control_map.keys(), tofind = search_text)
pywinauto.findbestmatch.MatchError: Could not find 'Maple' in 'dict_keys([])'
>>> maple.Maple.print_control_identifiers()
Traceback (most recent call last):
  File "C:\Users\mas\AppData\Local\Programs\Python\Python36-32\lib\site-packages\pywinauto\application.py", line 246, in __resolve_control
    criteria)
  File "C:\Users\mas\AppData\Local\Programs\Python\Python36-32\lib\site-packages\pywinauto\timings.py", line 453, in wait_until_passes
    raise err
pywinauto.timings.TimeoutError

During handling of the above exception, another exception occurred:

Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
  File "C:\Users\mas\AppData\Local\Programs\Python\Python36-32\lib\site-packages\pywinauto\application.py", line 585, in print_control_identifiers
    this_ctrl = self.__resolve_control(self.criteria)[-1]
  File "C:\Users\mas\AppData\Local\Programs\Python\Python36-32\lib\site-packages\pywinauto\application.py", line 249, in __resolve_control
    raise e.original_exception
  File "C:\Users\mas\AppData\Local\Programs\Python\Python36-32\lib\site-packages\pywinauto\timings.py", line 431, in wait_until_passes
    func_val = func(*args, **kwargs)
  File "C:\Users\mas\AppData\Local\Programs\Python\Python36-32\lib\site-packages\pywinauto\application.py", line 191, in __get_ctrl
    dialog = self.backend.generic_wrapper_class(findwindows.find_element(**criteria[0]))
  File "C:\Users\mas\AppData\Local\Programs\Python\Python36-32\lib\site-packages\pywinauto\findwindows.py", line 84, in find_element
    elements = find_elements(**kwargs)
  File "C:\Users\mas\AppData\Local\Programs\Python\Python36-32\lib\site-packages\pywinauto\findwindows.py", line 303, in find_elements
    elements = findbestmatch.find_best_control_matches(best_match, wrapped_elems)
  File "C:\Users\mas\AppData\Local\Programs\Python\Python36-32\lib\site-packages\pywinauto\findbestmatch.py", line 533, in find_best_control_matches
    raise MatchError(items = name_control_map.keys(), tofind = search_text)
pywinauto.findbestmatch.MatchError: Could not find 'Maple' in 'dict_keys([])'
>>>

 

I've made calculation as array := function(array1,array2). Then summ of all array[i] all in one cycle. If I look in summ variable I see fu(0+fu() +.. agebraical representation. I tried evalf(summ). still algebraical. How to derive numerically?

Hi

I want to solve quadratic eqution involving more than 2 parameters...want to analize unique soltuions and real roots also want to plot the real and unique region on graphs ....thanx

the equation is -delta*(Q*S*alpha*b-a*alpha^2+M*c+b*delta) where alpha is the varible and rest are paramters 

 


 

restart

PI := proc (p, e, q) options operator, arrow; p*S(p, e, q)+v*(q-S(p, e, q))-w*q-g(e)+(w-c)*q end proc

proc (p, e, q) options operator, arrow; p*S(p, e, q)+v*(q-S(p, e, q))-w*q-g(e)+(w-c)*q end proc

(1)

S := proc (p, e, q) options operator, arrow; q-(int(F(x), x = 0 .. q)) end proc

proc (p, e, q) options operator, arrow; q-(int(F(x), x = 0 .. q)) end proc

(2)

NULL

PI(p, e, q)

p*(q-(int(F(x), x = 0 .. q)))+v*(int(F(x), x = 0 .. q))-w*q-g(e)+(w-c)*q

(3)

g := proc (e) options operator, arrow; (1/2)*mu*e^2 end proc

proc (e) options operator, arrow; (1/2)*mu*e^2 end proc

(4)

``

F := proc (x) options operator, arrow; int(f(x), x = 0 .. q) end proc

proc (x) options operator, arrow; int(f(x), x = 0 .. q) end proc

(5)

P := proc (p, e, q) options operator, arrow; simplify(eval(PI(p, e, q), [alpha = 50, w = 10, mu = 10, c = 5, v = 1, f(x) = 1/2])) end proc

proc (p, e, q) options operator, arrow; simplify(eval(PI(p, e, q), [alpha = 50, w = 10, mu = 10, c = 5, v = 1, f(x) = 1/2])) end proc

(6)

Diff_p := diff(P(p, e, q), p)

q-(1/2)*q^2

(7)

Diff_e := diff(P(p, e, q), e)

-10*e

(8)

Diff_z := diff(P(p, e, q), q)

-p*q+p+q-5

(9)

``

``


 

Download Profit_code.mw

 

 

 

why i can not evaluate 29 polynomial. maple try to evaluate last 7hr, how many time required too solve it?

 

How to change the numbers shown in the diagram shapes from y=0.5- to rigth form y=-0.5a.mw

Download a.mw


 

 

 

 

 

 

Hello,

Please , how can we plot two figures with different X-axis and the same Y-axis ?

Thank you

 

general_solution.mwI want to calculate the diff equations numerical solutions at z=500 with calling the integrals with limits -500..Z and i want the datefile of resualts

 

Dear authors,
How to solve this ode problem.

Download link ode.mw

In this problem the boundary condition is

Note: F=g in our problem.

eta approaches N.

Thank you.

 

Hello, I need to figure out what theta is through this matrix:

https://imgur.com/RldbcJD

Should I use a solve command for this?

Executing the entire worksheet several times I obtain random results for Threads:-Seq

restart;

N:=10^3;
f:= (a,b) -> add(evalf(j), j=a..b);

1000

 

proc (a, b) options operator, arrow; add(evalf(j), j = a .. b) end proc

(1)

seq(f(k*N/4+1,(k+1)*N/4), k=0..3);

31375., 93875., 156375., 218875.

(2)

Threads:-Seq(f(k*N/4+1,(k+1)*N/4), k=0..3);

31218.+j, 93875., 156375., 218875.

(3)

Threads:-Seq(f(k*N/4+1,(k+1)*N/4), k=0..3);

31375., 93875., 156375., 218875.

(4)

Threads:-Seq(f(k*N/4+1,(k+1)*N/4), k=0..3);

31900., 94170., 156375., 218875.

(5)

 


Download threads!.mw

 

I need to find all integer solutions of these multivariable equations (and many more similar equations)

I have the boundary conditions that b-1 ≥ a1 > a2 ≥ 0

How can I do this in Maple?

For context, b is a base and a1 and a2 are digits in a b-adic number where a1 is bigger than a2. Solutions to these equations correspond to numbers that have a particular property.

 

I have posted this question on math.stackexchange, but saught an algebraic approach rather than a computational one. Here it is shown that a1 and a2 are linear functions of b. This is where the families of solutions come in. Mathloves answer is detailed and potentially useful in regards to formatting the answer.

https://math.stackexchange.com/questions/3001095/integer-solutions-of-a-variable-coefficient-polynomial

 

Thank you for any help / advice. Ben

I have to use the Chinese Remainder Theorem but once I have found m^e I cant seem to figure out a way that works to get just the message without the exponent. I assumed that the exponent is 3 since the message was encrypted 3 different times. How can I do this with Maple?

CRA_project.mw

1 2 3 4 5 6 7 Last Page 1 of 234